prvi i drugi zakon termodinamike (kombinovani ... - MASINAC.org

zbirka zadataka iz termodinamike strana 4!5/4/!Meteor temperature!U>4111!L-!brzinom x>21!ln0t ule}e u ledeni breg temperature!U>384!L/!Masa meteora je!n n >21!lh-!a specifi~ni toplotni kapacitet!d n >1/9!lK0lhL/!Odrediti:a) koli~inu toplote koju meteor preda ledenom breguc*! promenu entropije izolovanog sistema koji ~ine meteor i ledeni breg!d*! masu otopqenog leda (toplota topqewa leda iznosi s>443/5!lK0lh)!!meteor x>21!ln0t!ledeni brega)!prvi zakon termodinamike za proces koji se de{ava sa meteorom:!x3− x2= n n n3 n2 + n ⋅ !3! R 23 !>!∆V 23 !,!X 23 !,!∆F l23 ! R n ⋅ d ⋅ ( U − U )4 321 ⋅2123 21 ⋅ 1/9 ⋅ 384 − 4111 − 21 ⋅ ⋅21! ( )( ) −4!b)!R23= >− 6/329⋅21lK!3lK! ∆Ttjtufn= ∆Tnfufps+ ∆Tmfe>///>−2:/286!,2:22/466>29:9/29! !LUn3384lK! ∆ Tnfufps= nn⋅ dnmo > 21 ⋅ 1/9⋅mo>!−2:/286! !U4111L!c)mn2R236/329 ⋅21∆ T mfe = >U 384! R = n ⋅ ! ⇒!!23 m sm6>2:22/46! LlK !R236/329 ⋅21n m = >s 443/5m6>2681!lh!933dipl.ing. @eqko Ciganovi}{fmlp@fvofu/zv