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PONAŠANJE BRODA NA TALASIMA____________________________Formula Heridzme i Bukelmana izvedena je podpretpostavkom da brod plovi pramcem karegularnim talasima...Dodatni otpor na neregularnim talasima, možese, na osnovu principa superpozicije, izračunatikaoNΔR= ∑ ΔRn( ωn)n=1Za dodatni otpor na neregularnim talasima,međutim, najčešće se koristi nešto drugačija,integralna formula.Izraz se transformišeΔRn( ωn)2ΔRn( ωn) = ⋅ An( ωn)=2An( ωn)2= 2Δr ( ω ) S ( ω ) Δωgde je iskorišćenoΔr( ω ) =nnn n n n pΔRAA ( ω ) = 2S ( ω ) ⋅Δωn n n n pnnDodatni otpor na neregularnimtalasima je tadaN∑n = 12ΔR= 2 Δr ( ω ) ⋅S( ω ) ΔωAkoformula postaje∫n n n n pΔω → dωp∞R = 2 2r (0p) ST( p)⋅dpΔ Δ ω ω ωTo je formula Herizme i Bukelmanaza dodatni otpor broda naneregularnim talasima...Treba naći Δr u funkciji prividnefrekvencije... (igra, na neki način,ulogu prenosne funkcije...)pPREDAVANJA 2009. 171
PONAŠANJE BRODA NA TALASIMA____________________________Primer ukupnog otpora na neregularnimtalasimakontejnerski broda L = 175 m,Sprega ponašanja broda na talasima ipropulzije broda...Potisak propelera u slobodnoj vožnji T prodređuje se iz bezdimenzione karakteristike...TprKT =2 4ρn Dprv A( 1−w) vJ = =oDn DnprprKojom brzinom v o napreduje brod?Potrebno je odrediti potisak propelera T pr ...i naneti ga u dijagram...VažiPresek krivih R i( )T 1− t = RprT ′prT ′prdaje brzinu plovidbe...Pretpostavimo (npr) da motor radi na max.režimu, i da je pri tome n = n MCRZa (pretpostavljenu) brzinu v o ...vo → J → KT →Tpr →T′prsledi tačka u dijagramu...Da li motor može da razvije n MCR ??PREDAVANJA 2009. 172
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