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PONAŠANJE BRODA NA TALASIMA____________________________Možemo pisatiJ = D⋅jx2xωϕ=1 gMGj 1+κxϕPeriod se (zbog MG) menja u širokimgranicama...T = 6 − ϕ40 s2π1+κT > Tza uobičajeneϕϕ ζeTϕ= = 2πjxbrodske formeωϕgMGmϕκϕ= = O( 0,1) 1Dobili veoma slične rezultate za ζ (), t ϕ () tGJxDiferencijalne jednačine istog tipa...2πj poznata formulaxT≈ϕ iz predmeta javljaju se dodatne mese, prigušenja,gMG Plovnost isopstvene frekvencije...stabilitet broda...Treba uočiti razlike ovih kretanjaj x= c ⋅Bc = 0,3 – 0,4κ = O() 1 = ? κ 1Prema IMO Kriterijumu u vremenskihe uslova...c =g ⎛⎜0,372+ 0,023π ⎝BT− 0,043L100⎞⎟⎠ζΨ < Ψ 1 ,Ψ ϕ =??ϕζζ G() t 1ϕ()t 1?ϕPREDAVANJA 2009. 15
PONAŠANJE BRODA NA TALASIMA____________________________Dinamičke reakcijeUticaj utovara teretav = r⋅ ϕ a = r⋅ ϕ a = r⋅ ϕ2A,AN,AT2Fz = mg+ my Aϕ−mzAϕ2F = mgϕ−mz ϕ−my ϕy A AOpet postoje statičke i dinamičke reakcije...Dodatno, ukoliko je teret slobodno oslonjen(nefiksiran), javlja se problem proklizavanja...Fy> μFzMG =D MG −m ( z −z)oo o o P SDx x o oo+ m2 2J = J + G G D + PG mjx=DoJx+ mSlično i pomeranje tereta...PREDAVANJA 2009. 16
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