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PONAŠANJE BRODA NA TALASIMA____________________________Sopstveni period poniranja može seizraziti kaoδT1( + κζ)Tζ= 2π= 2πKζTα gδ( 1 + κζ)Kζ= = ( 0,37 ÷ 0,47) m / sα gT = ( 2,3 ÷ ζ3)T T = 3 − ζ13 sI prigušenje ne možemo tačno č odreditiditibez detaljnijeg proračuna...Ali, prigušenje je posledica talasa...veći talasi koje stvara brod svojimponiranjem, veće prigušenje...Da li veće prigušenje pri poniranjuimaju brodovi sa uspravnim ilitrouglastim rebrima...?Ključni parametar je vertikalni prizmatičnikoeficijentδϕ =Veće ć φ v , manje prigušenje...vαKod uobičajenih brodskih formiDinamičke reakcijeΨζ= 0,15 −0,25ζ () t = ζ () t = ζ e sin( ω t−γ)A G oma = F −mgANF = mg + m tNζ () A...−μ t ζζΨ ζ 1 ?ζVažinζ⎡⎣V⎤⎦> nζ⎡⎣U⎤⎦statička + dinamička reakcijaPREDAVANJA 2009. 13
PONAŠANJE BRODA NA TALASIMA____________________________2.2 Valjanje broda( Jx+ m ) ϕ + Mr( ϕϕ)+ Mst( ϕ)= 0M ≈ gD⋅MG ⋅ϕ, za ϕ 1st= ϕ + ϕ ϕ + ≈ ϕ( 1 ) ( 2)M n n ...nr ϕ ϕ ϕ( J + m ) ϕ+ n ϕ+ gD⋅MG⋅ ϕ = 0xϕϕPretpostavljamo ζG = 0,ψ = 0Tražimo φ(t) = ?VažiJ ϕ = MM = M + M′( o )x x xM( o) =−M ( ϕ)xM ′xϕxst= −m ϕ− Mxr(ϕ) ω =ϕ ϕ+ μ ϕ+ ω ϕ =22 ϕϕ0gDMGnϕμϕ=J + m 2( J + m )x−μ ϕ tϕϕ () t = ϕ e sin( ω t+γ)oϕ( ωϕ≈ ωϕ)μϕΨϕ= = Ο( 0,1) 1ωϕmalo, ali na njega utiče i trenje...ϕxϕPREDAVANJA 2009. 14
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