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PONAŠANJE BRODA NA TALASIMA____________________________Pretpostavićemo da je dužina talasadaleko veća od širine brodaλT BTada važiaϕ ≈ 1A diferencijalna jednačina valjanja glasi2 2 ϕ + 2μ ϕ + ω ϕ = αω cosωtRešenje jeϕ ϕ o ϕϕ() t = ϕ cos( ω t−γϕ)Izraz za prenosnu funkciju valjanja glasi2= ϕoϕϕα= =2o2 2 2 2ω − ω + 4μϕωTP=oω( ϕ T )1TTa fazni pomeraj valjanja γ φ iznosiγϕgde je2μϕωT2Ψ ϕΛϕ= arctg = arctg2 2 2ω −ω 1 −ΛϕΛTωTϕ = =ωϕTTNa osnovu disperzione relacije, važiω = gk =2TT2πgλtako da se prenosna funkcija može izraziti i uoblikuo= =( 1 2 ) 242 2ϕ− Λϕ + ΨϕΛαo2ϕ( ϕ T )PϕT2ϕϕTωλT2ϕωλ − 2πg + 8πgμ λϕTodakle sledi amplituda valjanja φ oPREDAVANJA 2009. 99
PONAŠANJE BRODA NA TALASIMA____________________________Dijagrami prenosne funkcije i faznogpomeraja su...Dijagrami se odnose na jedan brod natl talasima svih ihfrekvencija, odnosno svihtalasnih dužina.Brod na jednom regularnom talasupredstavlja tačku u dijagramima...Iako se prenosne funkcije, zbog različitihprigušenja i različitih sopstvenihfrekvencija, razlikuju od broda dobroda...sve imaju neke bitne zajedničkekarakteristike...PREDAVANJA 2009. 100
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