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RIJEÅ ENI ZADACI IZ MATEMATIKE

RIJEÅ ENI ZADACI IZ MATEMATIKE

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15. Koristeći definiciju derivacije, nadite derivaciju funkcije f(x) = √ 2x + 1 utočki x 0 = 4.Rješenje:limh→0f ′ f(x + h) − f(x)(x) = lim√ h→0√h2(x + h) + 1 − 2x + 1·h=√2(x + h) + 1 +√ 2x + 1√2(x + h) + 1 +√ 2x + 1== limh→02(x + h) + 1 − (2x + 1)h( √ 2x + 2h + 1 + √ 2x + 1) == limh→02x + 2h + 1 − 2x − 1h( √ 2x + 2h + 1 + √ 2x + 1) =2= lim √ √ =h→0 2x + 2h + 1 + 2x + 12√ 2x + 2 · 0 + 1 +√ 2x + 1=f ′ (4) =1√ = √ 1 = 1 2 · 4 + 1 9 322 √ 2x + 1 = 1√ 2x + 113

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