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Avditorne vaje - LES

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16.4.2012Magnetni krogi IIIzračunamo magnetni pretok. Izhajamo iz magnetno poljske jakosti:H l + H δδ = I Nj jKer vzdolž cele poti teče enak magnetni pretok, in je tudi presekkanala enak, mora biti povsod enaka gostota magnetnega pretoka:B j= Bδµ µ Hr 0 jµrµ0H j= µ0Hδ⇒ Hδ= = µrµ0H l µ H δ = I Nj j+r jHjI NHj=l + µ δjr7Magnetni krogi IIGostota magnetnega pretoka v jedru znaša:I NB = µ0µrHj= µ0µrl + µ δMagnetni pretok:I NΦ = B S = µ0µrSl + µ δMagnetna upornost:I NRm=Φ=µjjI NI NµrSl + µ δ0jrrr8Magnetni krogi IIEnačbo uredimo:lj+ µrδRm=µ µ S0rMagnetni upornost razdelimo nadva dela:lj+ µrδlj µrδRm= = +µ0µrSµ0µrSµ0µrSlj δRm= +µ0µrSµ S123 { 0UpornostjedraUpornostzračne reže2⋅43+2⋅58− 2 + 2 π 8l =1000j=0,25027 m93

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