1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...

136{( X ,..., X ) X > K , X < }1 5 1 K2(4{( X ,..., X ) X ≠ K} . 8 50 (22؟ %20 0/04Z0=1 8×4250 50−0/16Z0=1 8×4250 50: a ∑(X i − X)Yâ =i∑(X X)2 i −â =∑(X i Y i )∑(X X)2 i − n2 1 nSY= ∑ (Yi − Ŷ)n − 2 i=12 1 nSY= ∑ (Yi − Y)n − 2 i=1X-2-1021Y413-1-2( 2(41Yi= aXi + e,i = 1,22 (22 (4( 2(4b,a Y = aX + b +5(3−0/04Z0=1 8×4250 500/16Z0=1 8×4250 50(1(3,...,n (23∑(X i − X)Yâ =i∑ X2i∑(X i Y )â = i∑ X2i(1(3e (24: 2 1 nS)2Y= ∑ (Yi − Ŷn −1i=12 1 nSY= ∑ (Yi − Ŷ)n i=1Y = aX +(12 (3b (25 ( â, bˆ) = ( 1/3,−1)( â, bˆ) = ( 1/3,1)( â, bˆ) = ( −1/3,1)( â, bˆ) = ( −1/3,−1)(1( 2(3(4