1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...
1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ... 1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...
50X i123∑22 ∑(Xi−X)S =n−118 20219 20220 20221 20222 2022 ( − ) + ( − ) + ( − ) + ( − ) + ( − )S =5−125(2∑ X25 2 25 i )− =2−= 1∑(XX) ∑ Xiiii= 1i=1 nf in0/250/50/251fiXin0/2510/752f X2i in0/2522/254/552= 20−= 1925= 2/5. 3 (10. 4(11. 4 (12. 2 (13. 2 (14n∑ f i X iX =i=1= 2nn2n∑ f i X f i Xi∑ iδ2=i=1− (i=1)2= 4/5 − 22= 0/5n n150 -157157 -164164 -171171 -178178 -185. . 1 (15f i Fi15 1525 4030 7020 9010 100100. 1 (16
51 n 100= = 502 2n− Fi −1m =2ai + × lfi50−40m = 164 + × 7 = 166 / 330y = ax +b x . 3 (17a X δ y =αiaδ2a2δ2x δ y = xy = ax + b. 4-6-8-10-12 ( = 6 − 4 = 2) . 2 (18360×f ×= i 360 15= = 60°N 90. 3 (19. 1 (20. 4 (21[(22−1)2+ (( −1)2−1)2+ (( −2)2−1)2] b4b(X2)24b (X2∑ 3 −1= 3 ∑ −1)= 54i=2i=1 .X = m =( M < m
- Page 1 and 2: 43 (4 (3 (1 (2 (1
- Page 3 and 4: 45 20 100 (16( ) 150 -
- Page 5 and 6: 47 (2 (4 14 . . (2.
- Page 7: 49 . 2 (1α i= 360×
- Page 11 and 12: 53fi= ( < < ) . (2( < < ) .
- Page 13 and 14: 55P(AU B)2 1P(B) = , P(A) =3 372(4(
- Page 15 and 16: 576! (44× ! 3!(3 . 3 ! × 2!
- Page 17 and 18: 59 4 3 . 21 (1
- Page 19 and 20: 611 81−= ⇒ k = 3 ⇒ µ − kδ
- Page 21 and 22: 63 P ( ) = P( )3 4 3 6 1P ( )
- Page 23 and 24: 65 4 1 33P(W 1 ) =7 3 2 4P(B1
- Page 25 and 26: 67X = xP (X =x) (435 (4 E (
- Page 27 and 28: 69 1000 δx= 2µx 770
- Page 29 and 30: 71Var(y) = a2Var(x) = ( −2)2× 1/
- Page 31 and 32: 73xy012f (y) ( (11 2 3 6 x-18 8
- Page 33 and 34: 75 a . 3 (8:
- Page 35 and 36: 77 ⎛4⎞⎛66⎞⎛4⎞⎛66⎞
- Page 37 and 38: 797(49 ( E(X) = λ)100−1−e λ(4
- Page 39 and 40: 81 . . 3 (1λ x = δ
- Page 41 and 42: 83E(x) = np = 43 / 2Var(x) = npq =
- Page 43 and 44: 85e−λλxP(x) =X!P(X ≥ 2)= 1−
- Page 45 and 46: 87f (x) =1µ = δ =λ . .
- Page 47 and 48: 89 P( − a < z < a)0/921=2(4 6
- Page 49 and 50: 9122− (4(399 1818(40/6587 (
- Page 51 and 52: 93 1 3P ( −a< z < a) = 2 φ a
- Page 53 and 54: 95P − PP(P < 0/6)= P(Z < ) = P(Z
- Page 55 and 56: 97 X . δ = 2 µ =10 (1 (1
- Page 57 and 58: 99. (4 n1 + n2−2 (3 X
50X i123∑22 ∑(Xi−X)S =n−118 20219 20220 20221 20222 2022 ( − ) + ( − ) + ( − ) + ( − ) + ( − )S =5−125(2∑ X25 2 25 i )− =2−= 1∑(XX) ∑ Xiiii= 1i=1 nf in0/250/50/251fiXin0/2510/752f X2i in0/2522/254/552= 20−= 1925= 2/5. 3 (10. 4(11. 4 (12. 2 (13. 2 (14n∑ f i X iX =i=1= 2nn2n∑ f i X f i Xi∑ iδ2=i=1− (i=1)2= 4/5 − 22= 0/5n n150 -157157 -164164 -171171 -178178 -185. . 1 (15f i Fi15 1525 4030 7020 9010 100100. 1 (16
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