1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...

117 . X y . r=1 . 4 (1X . 2 (2X y = 3 + 0/4x⇒ 4/6 = 3 + 0/4x⇒ x = 4. -1 +1 . 1 (3 y X . 3 (4. ∑ x 12 ∑ y 6x = i = = 4 y = i = = 2n 3n 3∑(X − X)(y − y)r = i i ⇒∑(X − X)2∑(y − y)2i i[(2 − 4)(3 − 2)+ ( 4 − 4)(2 − 2)+ ( 6 − 4)(1−2)]= −1⎡(2 − 4)2+ ( 4 − 4)2+ ( 6 − 4)2⎤⋅ ⎡(3 − 2)2+ ( 2 − 2)2+ ( 1−2)2⎤⎢⎣⎥⎦ ⎢⎣⎥⎦. 1 (5Sxyβ =Sxx876= = 1/4157 ≈1/42618/75αˆ = y − βˆx = 2/42 −1/42(1/75)= −0/085ŷ = βˆx + αˆ = 1/42x−0/085. 3 (6 y x . 3 (7. . 4 (8