1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...
1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...
1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...
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110. 0/05 H 1 H0 (3. 0/05 H 1 H0 (4 (18: H0 α = 0/05 . X0123<strong>45</strong>P(X / θ0)0/050/050/850/030/020P(X / θ0)0/090/050/020/010/010/01X = 3(4X = 0 5(3X = 2(2X = 1(1