1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...
1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...
1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...
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97 X . δ = 2 µ =10 (1 (1014) X n =16 0/5228 (<strong>45</strong>∑ X2 = i1S =0/ 4120 (40/0228 (35∑ X i1S = 2/ 58= 20,0/4772 (20/5 (1n =15 (2 . (3S = 2/15(2S =1/9(1 0/95 (3( 1/572/29) (4(1/894/07) (3(2/293/47) (2(1/573/47) (1 S 2 p S1 = S2= 2,n2= 17,n1= 10 (4148495(4(32 (2 4 (1275 (5F (4χ 2 (3t (2 . 3/253/355 98 δ2P1−P2: S = 3 , X =1 9(-0/1152/115) (2(-2/3554/355) (4 P1( 1−P1) P2( 1−P2)= +n1n2 (1t (6 (-0/072/07) (1(-2/254/25) (3P 2 P 1 (7P1 − P 2 (22 P1( 1−P1) + P2( 1−Pδ =2P 1−P2n1+ n2)(1
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