1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...

93 1 3P ( −a< z < a) = 2 φ a −1= ⇒ φ a = ⇒ a = 0/682 4 . 1 (1X − µ Z = . 3 (2δ. δxδ = xn= 5 = 125X − µZ =δX . 4 (3 . 4(4. 9 −1011−10P(9 < x < 11)= P( < Z < ) = P( −1 9 ) = P(Z > ) = P(Z > −1)= 1−φ−1= φ = 0/84131P(Z < −a)= 1−φ a =P( −a< Z < a) = 2φ a38⇒ φ a−1= 2×58=58−1=28=14. 3(5. 3(61 1P( − a < Z < a) = 2 P( −a< Z < 0)= 2×=8 4 Z 1 0/5 1 . 1(7. 0/5 Z 1 2 . -1− a001a