12.07.2015 Views

1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...

1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...

1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...

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- 9/6 90P ( 1/5 ≥ Z ≥ Z1 ) = 0/3(4P ( −2 ≤ Z ≤ Z1)= 0/75 , 100 10 (8(3 29/695 (465 (347/5 (25 (1: Z = 2 Z = −2 (90/6826 (40/9544 (30/98 (20/9973 (1 . , %30 (10 , 200 50 0 /9463(40/9382 (30/4474 (20/4382 (1 ( µ − 2 δ,µ + 2δ) (11% 68(4%95 (3%99/7 (2%75 (1 δ2= 36,µ =10 X (12 P(4 < x < 16)0 /26(40/84 (30/34 (20/68 (1 150 . %70 (13 , 0/6 0 /0035(40/5 (30/5993 (20/0062 (1 Y = 10Z− 5 Z (14-5 (415 (35 (210 (1: Y (14) (155 (410 (3100 (295 (1 9 10 X (16: X = 12

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