1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...

88f (x,θ) =nθn− ∑ x i1θne−θ∑xi⇒ Lnf (x,θ) = nLnθ − θ∑xin= 0⇒n − θ∑x i1n 1= 0⇒θˆ = ⇒ θˆ =∑ xi xθLnf (x,θ)dθ=n = 5 ,X = 5,K= 7,N = 10 . (1⎛7⎞⎛3⎞7!3!⎜ ⎟⎜⎟ ×CkCN−K5 0 5 7 − 5 0 3 −01= − ⎝ ⎠⎝⎠ !( )! !( )!P(x) x n x = ==CN ⎛10⎞10!12n ⎜ ⎟⎝5⎠5!(10−5)!k 7µ = E(x) = n = 5×= 3 / 5N 102k N − k N − n 7 10−7 10−5δ = Var(x) = n ⋅ ⋅ = 5×× × = 0/58N N N −110 10 10−1