1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...

85e−λλxP(x) =X!P(X ≥ 2)= 1−P(X < 2)= 1−P(X ≤ 1)= 1−e−2⇒ 1−(0!P =21000×02212e−2+1!=13000121n = 3000 , λ = 3000×= 13000e−112e−2P(X = 2)= =2!2 () λP(x = 1)= e−λλ−2) = 1−3ex = 1 . 1 (26[ P(X = 0)+ P(X = 1)]: . 3 (27λ = np . 1 (28 . ∂p x (x)= −e−λλ + e−λ⇒ −e−λλ + e−λ∂λ2P = n → ∞ ⇒ p →0np(x = 0)= e−22λ = n × = 2n. = 0⇒e−λ(λ −1)= 0⇒λ = 1. 2 (29 . . 2 (30⎛5−1⎞P (x) = ⎜ ⎟ × 0/13× 0/92= 0/00486⎝3−1⎠. 3 (31