1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...
1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ... 1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...
801− e − 1/5(4 f (X)e −1/ 5= θe−θx, X− x(4(3e −0/ 5(21− e − 0/ 5 (1> 0 θ (42x: (31−xn (21x(1 5 . 7 10 (1: 5 (. (
81 . . 3 (1λ x = δ 2 x = np. 2 ( 2 . 1λ = np = 100×= 1100λxe−λ10e−1P(x) = ⇒ P(x = 0)= = e−1x!1. λ = np . 4 (3⎛n⎞P(X = x) ⎜ ⎟Pxqn−x⎝ x⎠⎛6⎞1 4 1 6 4 1= ⎜ ⎟() ( 1−)−= 15()6⎝4⎠2 2 2: . 2 (4⎛n⎞P(x) = ⎜ ⎟Pxqn−1⎝ x ⎠⎛15⎞1 6 1 15 1 15 1115 6 ⎛ ⎞ 15 !P(x) = ⎜ ⎟() ( − )−= ⎜ ⎟() = × ( )15= 0/15⎝6⎠ 2 2 ⎝6⎠ 2 96 ! ! 2. . 1 (5µ = np = 25 × 0/3 = 7 / 5λ = S2= 1λxe−λ1e−1P(x) = ⇒ P( 1)= = e−1= 0/368X!1!12e−10/368P ( 2)= = = 0/1842!2. 2 (6
- Page 1 and 2: 43 (4 (3 (1 (2 (1
- Page 3 and 4: 45 20 100 (16( ) 150 -
- Page 5 and 6: 47 (2 (4 14 . . (2.
- Page 7 and 8: 49 . 2 (1α i= 360×
- Page 9 and 10: 51 n 100= = 502 2n− Fi −1m =2
- Page 11 and 12: 53fi= ( < < ) . (2( < < ) .
- Page 13 and 14: 55P(AU B)2 1P(B) = , P(A) =3 372(4(
- Page 15 and 16: 576! (44× ! 3!(3 . 3 ! × 2!
- Page 17 and 18: 59 4 3 . 21 (1
- Page 19 and 20: 611 81−= ⇒ k = 3 ⇒ µ − kδ
- Page 21 and 22: 63 P ( ) = P( )3 4 3 6 1P ( )
- Page 23 and 24: 65 4 1 33P(W 1 ) =7 3 2 4P(B1
- Page 25 and 26: 67X = xP (X =x) (435 (4 E (
- Page 27 and 28: 69 1000 δx= 2µx 770
- Page 29 and 30: 71Var(y) = a2Var(x) = ( −2)2× 1/
- Page 31 and 32: 73xy012f (y) ( (11 2 3 6 x-18 8
- Page 33 and 34: 75 a . 3 (8:
- Page 35 and 36: 77 ⎛4⎞⎛66⎞⎛4⎞⎛66⎞
- Page 37: 797(49 ( E(X) = λ)100−1−e λ(4
- Page 41 and 42: 83E(x) = np = 43 / 2Var(x) = npq =
- Page 43 and 44: 85e−λλxP(x) =X!P(X ≥ 2)= 1−
- Page 45 and 46: 87f (x) =1µ = δ =λ . .
- Page 47 and 48: 89 P( − a < z < a)0/921=2(4 6
- Page 49 and 50: 9122− (4(399 1818(40/6587 (
- Page 51 and 52: 93 1 3P ( −a< z < a) = 2 φ a
- Page 53 and 54: 95P − PP(P < 0/6)= P(Z < ) = P(Z
- Page 55 and 56: 97 X . δ = 2 µ =10 (1 (1
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- Page 59 and 60: 101: P(X< 300): (4 E(Z4 )1(
- Page 61 and 62: 103 . 2 (7. 3 (8. 2 (9. 4 (
- Page 63 and 64: 105 f (x) =1b − a0a < x
- Page 65 and 66: 107 (4 (3 (2H 1 :
- Page 67 and 68: 1090/31250 (40/343 (3 . 100 0/
- Page 69 and 70: 111 . H 0 H 0 . 3 (1
- Page 71 and 72: 113 3 2 (4 Y = 3 +0/4X0〈r≤
- Page 73 and 74: 115 (4( r = 100r′)X(3 Y,Y( B = B
- Page 75 and 76: 117 . X y . r=1 .
- Page 77 and 78: 11921212102121012121212121212121012
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- Page 81 and 82: 123 13 (141Lnλ2(42Lnλ(31
- Page 83 and 84: 125 . 4 (10 37374
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- Page 87 and 88: 1291f (x) =θ (44X، 0< x < θ(4
81 . . 3 (1λ x = δ 2 x = np. 2 ( 2 . 1λ = np = 100×= 1100λxe−λ10e−1P(x) = ⇒ P(x = 0)= = e−1x!1. λ = np . 4 (3⎛n⎞P(X = x) ⎜ ⎟Pxqn−x⎝ x⎠⎛6⎞1 4 1 6 4 1= ⎜ ⎟() ( 1−)−= 15()6⎝4⎠2 2 2: . 2 (4⎛n⎞P(x) = ⎜ ⎟Pxqn−1⎝ x ⎠⎛15⎞1 6 1 15 1 15 1115 6 ⎛ ⎞ 15 !P(x) = ⎜ ⎟() ( − )−= ⎜ ⎟() = × ( )15= 0/15⎝6⎠ 2 2 ⎝6⎠ 2 96 ! ! 2. . 1 (5µ = np = 25 × 0/3 = 7 / 5λ = S2= 1λxe−λ1e−1P(x) = ⇒ P( 1)= = e−1= 0/368X!1!12e−10/368P ( 2)= = = 0/1842!2. 2 (6
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