1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...
1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...
1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...
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62n(A) = ( 4 −1)!× 2!= 12n(A)P(A) =n(S)=1224=125 ! =120. 1 (16. 2 (17. 1 (18P( 11) = ×2251+ ×249=210 2+2918 + 20= =903890=19<strong>45</strong>. 2 (19P ( 1 P(A U B) = P(A) + P(B) − P(A I B)P(A) ⋅ P(B) = 0/3 × 0/5 = 0/15: . 1 (201 2×9=2 5=19 19<strong>45</strong>. 2 (21⇒ P(A I B) = P(A) + P(B) − P(A U B) = 0/5 + 0/3 −0/65 = 0/15. BA P(AI B) = P(A) ⋅ P(B) . 3 (22 1 2 3! . 3 ! × 4! 6 B 4P (1) P() =P () 3 . 4! 1 A 3 ⋅ )1 . 1 (23