1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...
1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...
1( = @ 1( > 2( > 3( 4( > 2( 45 % @ @ > > > @ > > = > 1( 180 2( 162 3 ...
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53fi= ( < < ) . (2( < < ) . (3 i × ∑fi 1 (31F3 = 0/2×40 = 8 ⇒ F = F + F3⇒ F = 14 + 8 = 223 2 3. 1 (32 K =∑ f −3 i (x i x)Nδ3⇒K > 0⎯⎯→K = 0⎯⎯→K < 0⎯⎯→ n 1 1 2 1 1= + ⇒ = + ⇒ X = 96X H X1X2X H 80 120S′2SCV = = = 1⇒ X′2XX1 = X2= X3= X4= 1515 + 15 + 15 + 3X == 124n1X1+ n2X25 × 5 + 20×20X ==17n1+ n220+5CV xS = xµH ≤ G ≤ X8 = = 24. 3 (33. 1 (34: . 3 (35⇐ X ′ = X + K. 3 (36. 4 (37. 3 (38. 2 (39. 4 (40 4 3 . 1 (41 4 ( xi + 3)−12= 4xi: . 12 . . 4
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