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ÿêèé íàðîäèâñÿ â ëþòîìó. Ïàðàìåòð ì äîð³âíþº 2. Êîîðäèíàòè<br />

âåðøèí òðèêóòíèêà áóäóòü òàê³: À (–2, 4), Â (6, –2),<br />

Ñ (8, 7).<br />

Ðîçâ’ÿçàííÿ. 1) ³äñòàíü ì³æ äâîìà òî÷êàìè âèçíà-<br />

÷èìî çà äîïîìîãîþ ôîðìóëè (4.1.3 ). Çàñòîñîâóþ÷è ¿¿, çíàéäåìî<br />

äîâæèíó ñòîð³í À ³ ÀÑ:<br />

2 2 2<br />

2<br />

AB = ( 6-( - 2)<br />

) + (-2- 4) = 8 + (- 6)<br />

= 100 = 10 .<br />

2 2<br />

AC = ( 8+ 2) + ( 7- 4)<br />

= 109 .<br />

2) Ó â³äïîâ³äíîñò³ äî ï. 4.3.4 ð³âíÿííÿ ïðÿìî¿, ÿêà ïðîõîäèòü<br />

÷åðåç òî÷êè À ³ Â, òàêå:<br />

y- 4 x+<br />

2<br />

=<br />

-2- 4 6+ 2<br />

.<br />

Çâ³äêè 3õ +4ó − 10 = 0 (ÀÂ). Ùîá çíàéòè êóòîâèé êîåô³ö³ºíò<br />

k AB ïðÿìî¿ ÀÂ, ðîçâ’ÿæåìî îòðèìàíå ð³âíÿííÿ â³äíîñíî<br />

ó:<br />

ó = −3/4õ + 5/2, òàêèì ÷èíîì k AB = −3/4.<br />

Àíàëîã³÷íî çíàéäåìî ð³âíÿííÿ ïðÿìî¿ ÀÑ:<br />

3õ − 10ó + 46 = 0 ³ ïðÿìî¿ ÂÑ: 9x − 2y − 58 = 0. Êóòîâ³ êîåô³ö³ºíòè<br />

ïðÿìèõ ÀÑ ³ ÂÑ òàê³: k AÑ = 3/10, k ÂÑ =9/2.<br />

3) Âíóòð³øí³é êóò ïðè âåðøèí³ À ïîçíà÷èìî ÷åðåç α.<br />

42<br />

Òîä³, çàñòîñîâóþ÷è ôîðìóëó (4.3.8), çíàéäåìî, ùî tga= .<br />

31<br />

42<br />

Îòæå, øóêàíèé êóò a= arctg . 31<br />

4) Íåõàé D — ñåðåäèíà â³äð³çêó ÂÑ. Äëÿ âèçíà÷åííÿ<br />

êîîðäèíàò òî÷êè D çàñòîñóºìî ôîðìóëè (4.1.7) ä³ëåííÿ â³äð³çêà<br />

ïîïîëàì:<br />

6+ 8 - 2+<br />

7 5<br />

xD<br />

= = 7, yD<br />

= = .<br />

2 2 2<br />

Äàë³, çàñòîñîâóþ÷è ôîðìóëó (4.3.19) (ð³âíÿííÿ ïðÿìî¿,<br />

ÿêà ïðîõîäèòü ÷åðåç äâ³ òî÷êè), îòðèìàºìî ð³âíÿííÿ ìåä³àíè<br />

ÀD:<br />

y- 4 x+<br />

2<br />

= Þ x+ 6× y- 22 = 0 ( AD)<br />

.<br />

5 7+<br />

2<br />

- 4<br />

2<br />

5) Âèñîòà CP ïåðïåíäèêóëÿðíà ñòîðîí³ A (P — òî÷êà<br />

ïåðåòèíó ïåðïåíäèêóëÿðà ³ ñòîðîíè ÀÂ). Òîìó çà êðèòåð³-<br />

ºì ïåðïåíäèêóëÿðíîñò³ äâîõ ïðÿìèõ (äèâ. ï. 4.3.2) ¿õí³<br />

êóòîâ³ êîåô³ö³ºíòè ïîâ’ÿçàí³ ð³âí³ñòþ k CP = −1/k AB . Îñê³ëüêè<br />

ìè çíàéøëè ðàí³øå, ùî k AB = −3/4, òî k CP = 4/3. Çíàþ÷è<br />

êîîðäèíàòè òî÷êè Ñ (8, 7) ³ êóòîâèé êîåô³ö³ºíò k AB , çà ôîðìóëîþ<br />

(4.3.13) ñêëàäåìî ð³âíÿííÿ âèñîòè ÑÐ:<br />

ó − 7 = 4/3 (õ − 8) ⇒ 4õ − 3ó − 11 = 0 (ÑÐ).<br />

6) Ç êóðñó ìàòåìàòèêè ñåðåäíüî¿ øêîëè â³äîìî, ùî á³ñåêòðèñà<br />

êóòà òðèêóòíèêà ÀÂÑ ïðè âåðøèí³ À ìຠâëàñòèâ³ñòü<br />

AB BK<br />

= .<br />

AC KC<br />

Çã³äíî ç ðåçóëüòàòàìè ðîçâ’ÿçêó 1) ìàòèìåìî<br />

BK<br />

λ= =<br />

KC<br />

10 .<br />

109<br />

Òåïåð, çíàþ÷è êîîðäèíàòè òî÷îê  ³ Ñ, çà ôîðìóëàìè<br />

(4.1.6) çíàéäåìî êîîðäèíàòè òî÷êè L (îñíîâè á³ñåêòðèñè,<br />

ïðîâåäåíî¿ ç âåðøèíè À):<br />

80 + 6 109 70 -2 109<br />

xL<br />

= , yL<br />

=<br />

.<br />

10 + 109 10 + 109<br />

Ó â³äïîâ³äíîñò³ äî ôîðìóëè (4.3.18) îòðèìàºìî ð³âíÿííÿ<br />

á³ñåêòðèñè AL:<br />

30 - 6 109<br />

y- 4 = ( x+<br />

2 )( AL)<br />

.<br />

100 + 8 109<br />

120 121

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