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3.3. Êîðèñòóþ÷èñü ïðàâèëîì Êðàìåðà, ðîçâ’ÿçàòè ñèñòåìó<br />
ð³âíÿíü<br />
ì 3x- 3y+ 2z<br />
= 2,<br />
ï<br />
í4x- 5y+ 2z<br />
= 1,<br />
ïî<br />
5x- 6y+ 4z<br />
= 3.<br />
³äïîâ³äü: (1, 1, 1).<br />
3.4. Ðîçâ’ÿçàòè ìåòîäîì Ãàóññà ñèñòåìó ð³âíÿíü<br />
ì x1+ 2x2 + 3x3<br />
=<br />
7,<br />
ï<br />
í2x1+ 3x2- x3<br />
= 6,<br />
ï ïî 3x1+ x2- 4x3<br />
= 3.<br />
³äïîâ³äü: (2, 1, 1).<br />
3.5. Ðîçâ’ÿçàòè ìàòðè÷íèì ñïîñîáîì ñèñòåìè:<br />
³äïîâ³äü: (2, 1, 1).<br />
ì x- 2y+ z = 1,<br />
ï<br />
í2x+ y- z = 4,<br />
ïî<br />
x- y+ 2z<br />
= 3.<br />
ì 2x1+ x2 + 3x3 + 4x4<br />
=<br />
11,<br />
ï7x1+ 3x2 + 6x3 + 8x4<br />
= 24,<br />
í<br />
3x1+ 2x2 + 4x3 + 5x4<br />
= 14,<br />
ï<br />
ïî x1 + x2 + 3x3 + 4x4<br />
= 11.<br />
³äïîâ³äü: (1, –1, 2, 1).<br />
3.6. ×è ñóì³ñíà ñèñòåìà ð³âíÿíü? ßêùî ñóì³ñíà, òî ðîçâ’ÿçàòè<br />
¿¿:<br />
ì<br />
ï3x1+ 2x2 + x3+ x4<br />
= 1,<br />
í<br />
ï<br />
ïî 3x1+ 2x2-x3- 2x4<br />
= 2.<br />
³äïîâ³äü: (ñ 1 , ñ 2 ,4−9ñ 1 −6ñ 2 ,6ñ 1 +4ñ 2 −3).<br />
ì x1- x2 + x3- 2x4<br />
= 1,<br />
ï<br />
íx1 - x2 + 2x3 - x4<br />
= 2,<br />
ïî<br />
5x1- 5x2 + 8x3- 7x4<br />
= 3.<br />
³äïîâ³äü: íåñóì³ñíà.<br />
3.7. Âèçíà÷èòè ë³í³éíî íåçàëåæí³ ðîçâ’ÿçàííÿ ñèñòåìè<br />
ð³âíÿíü<br />
ì 2x1+ 3x2 + x3+ 2x4- x5<br />
=<br />
0,<br />
ï<br />
í3x1+ x2- 8x3+ 3x4 + 2x5<br />
= 0,<br />
ï ïî x1+ 2x2 + 2x3+ x4 + 6x5<br />
= 0.<br />
Âêàç³âêè:<br />
1. Çíàéòè ðàíã ñèñòåìè (â³í äîð³âíþº 3).<br />
2. Âèðàçèòè õ 1 , õ 2 , õ 3 ÷åðåç õ 4 ³ õ 5 .<br />
3. Ïîêëàñòè õ 4 = 1, õ 5 =0 ³ õ 4 = 0, õ 5 =1.<br />
4. Çíàéòè â³äïîâ³äí³ ÷èñëîâ³ çíà÷åííÿ õ 1 , õ 2 , õ 3 ³ õ' 1 , õ' 2 ,<br />
õ' 3 . Ñêëàñòè ë³í³éíó êîìá³íàö³þ õ = l 1 ó 1 + l 2 ó 2 , äå<br />
ó 1 =(õ 1 , õ 2 , õ 3 , 1, 0), ó 2 =(x 1 , x 2, x 3 , 0, 1).<br />
3.8. Ðîçâ’ÿçàòè òàê³ ñèñòåìè ð³âíÿíü ìàòðè÷íèì ìåòîäîì,<br />
çà ïðàâèëîì Êðàìåðà ³ çà ìåòîäîì Ãàóññà:<br />
³äïîâ³äü: (1, 2, 3).<br />
³äïîâ³äü: (1, 1, 1).<br />
ì Nx1- Nx2 + Nx3<br />
= 2 N,<br />
ï<br />
íNx1+ Nx2- Nx3<br />
= 0,<br />
ïî<br />
Nx1-Nx2- Nx3<br />
=-4 N.<br />
ì Nx1+ x2 + Nx3<br />
= 2N<br />
+ 1,<br />
ï<br />
í - x1 + Nx2 + x3<br />
= N,<br />
ïî<br />
Nx1- x2 + Nx3<br />
= 2N<br />
-1.<br />
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