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Ó â³äïîâ³äíîñò³ äî ïî÷àòêîâèõ óìîâ (11.6.19) ñêëàäåìî<br />

ñèñòåìó<br />

( ) ( )<br />

( ) ( )<br />

⎧ ⎪Cy 1 1<br />

x0 + Cy<br />

2 2<br />

x0 = y0<br />

⎨<br />

Cy′ 1 1<br />

x0 Cy′ 2 2<br />

x0 y′<br />

, (11.6.20)<br />

⎪⎩ + =<br />

0<br />

â ÿê³é C 1 ³ C 2 — íåâ³äîì³ ÷èñëà.<br />

Íåâàæêî ïîáà÷èòè, ùî âèçíà÷íèê ö³º¿ ñèñòåìè º âèçíà÷íèêîì<br />

Âðîíñüêîãî. Îñê³ëüêè çà óìîâîþ òåîðåìè ôóíêö³¿<br />

y 1 (x) ³ y 2 (x) — ë³í³éíî íåçàëåæí³ íà (a, b), òî çàâäÿêè òåîðåì³<br />

11.6.3 W(x 0 ) ≠ 0. Òîìó ñèñòåìà (11.6.20) ìຠºäèíèé ðîçâ’ÿçîê,<br />

ÿêèé ìè ïîçíà÷èìî òàê: C = C , C = C .<br />

0<br />

0<br />

ϳäñòàâëÿþ÷è<br />

0<br />

1<br />

1 1<br />

2 2<br />

0<br />

C ³ C â ð³âí³ñòü (11.6.18), îòðèìàºìî øóêàíèé ÷àñòèííèé<br />

2<br />

ðîçâ’ÿçîê ð³âíÿííÿ (11.3.1): y( x) C 0 y ( x) C 0 y ( x)<br />

= + , ÿêèé<br />

1 1 2 2<br />

çàäîâîëüíÿº ïî÷àòêîâ³ óìîâè (11.6.19). Öå ³ îçíà÷àº, ùî ðîçâ’ÿçîê<br />

(11.6.18) º çàãàëüíèì ðîçâ’ÿçêîì ð³âíÿííÿ (11.6.2).<br />

11.7. ˲ͲÉͲ ÄÈÔÅÐÅÍÖ²ÀËÜͲ<br />

вÂÍßÍÍß ÄÐÓÃÎÃÎ ÏÎÐßÄÊÓ<br />

Dz ÑÒÀËÈÌÈ ÊÎÅÔ²Ö²ªÍÒÀÌÈ<br />

11.7.1. Îäíîð³äí³ ð³âíÿííÿ<br />

Çàãàëüíèé âèãëÿä îäíîð³äíîãî ð³âíÿííÿ:<br />

y′′ + py′<br />

+ qy = 0 (x∈R), (11.7.1)<br />

äå p ³ q — ñòàë³.<br />

Çàãàëüíèé ðîçâ’ÿçîê äèôåðåíö³àëüíîãî ð³âíÿííÿ (11.7.1)<br />

ïîâ’ÿçàíèé ç ðîçâ’ÿçàííÿì õàðàêòåðèñòè÷íîãî ð³âíÿííÿ<br />

2<br />

k pk q<br />

+ + = 0 . (11.7.2)<br />

kx<br />

= , äå k — ñòàëà, ùî ï³äëÿãຠâè-<br />

ijéñíî, ïîêëàäåìî y e<br />

kx<br />

çíà÷åííþ. ϳäñòàâèìî y = e äî ð³âíÿííÿ (11.7.1). Âðàõîâóþ÷è,<br />

ùî y′ = ke , y′′ = k e îäåðæèìî, ùî<br />

kx<br />

2 kx<br />

∀x∈R:<br />

2<br />

( )<br />

kx<br />

e k + pk + q = 0 .<br />

kx<br />

kx<br />

Îñê³ëüêè e ≠ 0 ∀x∈R , òî ôóíêö³ÿ y = e áóäå ðîçâ’ÿçêîì<br />

ð³âíÿííÿ (11.7.1) ò³ëüêè ïðè çä³éñíåíí³ âèìîãè<br />

(11.7.2).  çàëåæíîñò³ â³ä âèäó êîðåí³â õàðàêòåðèñòè÷íîãî<br />

ð³âíÿííÿ (11.7.2) áóäóþòüñÿ ð³çí³ âèäè çàãàëüíîãî ðîçâ’ÿçêó<br />

ð³âíÿííÿ (11.7.1), àëå ñòðóêòóðà çàãàëüíîãî ðîçâ’ÿçêó<br />

ð³âíÿííÿ (11.7.1) îäíà é òà ñàìà:<br />

( ) ( )<br />

y = c y x + c y x ,<br />

1 1 2 2<br />

äå y 1 (x) ³ y 2 (x) ë³í³éíî íåçàëåæí³ (ËÍÇ) ðîçâ’ÿçêè ð³âíÿííÿ<br />

(11.7.1), à c 1 ³ c 2 — äîâ³ëüí³ ñòàë³.<br />

Ïîøóê ËÍÇ ðîçâ’ÿçê³â ð³âíÿííÿ (11.7.1) ïîâ’ÿçàíèé ç<br />

ìîæëèâèìè âàð³àíòàìè ðîçâ’ÿçêó õàðàêòåðèñòè÷íîãî ð³âíÿííÿ<br />

(11.7.2). Ö³ âàð³àíòè íàäàþòüñÿ ó íèæ÷å íàâåäåí³é<br />

òàáëèö³.<br />

Ïðèêëàä 11.7.1. Çíàéòè çàãàëüíèé ðîçâ’ÿçîê ð³âíÿííÿ<br />

y′′ − 5y′<br />

+ 6y<br />

= 0.<br />

Ðîçâ’ÿçàííÿ. Õàðàêòåðèñòè÷íå ð³âíÿííÿ, ÿêå â³äïîâ³äíå<br />

äàíîìó äèôåðåíö³àëüíîìó ð³âíÿííþ, ìຠâèãëÿä:<br />

2<br />

k − 5k<br />

+ 6 = 0.<br />

Éîãî êîðåí³ k 1 = 2, k 2 = 3. Ôóíäàìåíòàëüíà (ËÍÇ) ñèñòåìà<br />

2x<br />

3x<br />

÷àñòèííèõ ðîçâ’ÿçê³â: y1<br />

= e , y2<br />

= e . Çàãàëüíèé ðîçâ’ÿçîê<br />

ìຠâèãëÿä:<br />

y = c e + c e .<br />

2x<br />

3x<br />

1 1 2<br />

Ïðèêëàä 11.7.2. Çíàéòè çàãàëüíèé ðîçâ’ÿçîê ð³âíÿííÿ<br />

y′′ − 4y′<br />

+ 4y<br />

= 0.<br />

Ð î ç â ’ ÿ ç à í í ÿ. Õàðàêòåðèñòè÷íå ð³âíÿííÿ<br />

2<br />

k − 4k<br />

+ 4 = 0<br />

ìຠð³âí³ êîðåí³ k 1 = k 2 = 2. Ôóíäàìåíòàëüíà (ËÍÇ) ñèñòåìà<br />

÷àñòèííèõ ðîçâ’ÿçê³â:<br />

y = e , y = xe .<br />

2x<br />

2x<br />

1 2<br />

434 435

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