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 òî÷ö³ õ = 1 ôóíêö³ÿ ìຠìàêñèìóì: y′| x 0; y′| x>1 3/2 > 0; y| x = 3/2 = 1 + 4/3 – 4/9 = 17/9.<br />
Òî÷êà ïåðåãèíó (3/2, 17/9);<br />
2<br />
x + 2x−1<br />
6) ïåðåïèøåìî çàäàíó ôóíêö³þ ó âèãëÿä³ y =<br />
2 .<br />
x<br />
Âåðòèêàëüíà àñèìïòîòà: õ = 0. Çíàõîäèìî<br />
2<br />
y x + 2x−1<br />
k1,2 = lim = lim = 0, b<br />
3<br />
1,2<br />
= lim ( y− kx)<br />
= 1.<br />
x→±∞ x x→±∞ x<br />
x→±∞<br />
Ãîðèçîíòàëüíà àñèìïòîòà: ó =1;<br />
7) ãðàô³ê ôóíêö³¿ çîáðàæåíèé íà ðèñ. 7.5.<br />
Ðèñ. 7.5<br />
ÒÅÌÀ 8<br />
ÍÅÂÈÇÍÀ×ÅÍÈÉ ²ÍÒÅÃÐÀË ² ÉÎÃÎ<br />
×ÈÑËÅÍÍß<br />
8.1. ÏÅÐ<strong>²</strong>ÑÍÀ ² ÍÅÂÈÇÍÀ×ÅÍÈÉ<br />
²ÍÒÅÃÐÀË<br />
8.1.1. Ïðîáëåìí³ çàäà÷³<br />
Îñíîâíà çàäà÷à äèôåðåíö³àëüíîãî ÷èñëåííÿ ïîëÿãຠâ<br />
òîìó, ùîá â³ä çàäàíî¿ ôóíêö³¿ f(x) çíàéòè ¿¿ ïîõ³äíó. Çà<br />
äîïîìîãîþ äèôåðåíö³þâàííÿ ìîæíà ðîçâ’ÿçàòè òàê³ çàäà÷³:<br />
1 0 . ³äîìî çàêîí ïðÿìîë³í³éíîãî ðóõó ìàòåð³àëüíî¿ òî÷êè<br />
S = S(t). Òðåáà çíàéòè øâèäê³ñòü v â ìîìåíò ÷àñó t.<br />
Ðîçâ’ÿçàííÿ ïðîñòå: v(t) =S′(t).<br />
2 0 . ³äîìî ð³âíÿííÿ êðèâî¿ ó = f(x). Òðåáà çíàéòè êóò<br />
íàõèëó äîòè÷íî¿, ÿêà ïðîâåäåíà äî ãðàô³êà ôóíêö³¿ ó = f(x)<br />
÷åðåç äîâ³ëüíó òî÷êó M(x, f(x)). Ðîçâ’ÿçàííÿ òàêå:<br />
k(x) =f′(x).<br />
3 0 . Çàäàíî ôóíêö³þ ó = f(x). Òðåáà çíàéòè åëàñòè÷í³ñòü<br />
ö³º¿ ôóíêö³¿. Ðîçâ’ÿçàííÿ òàêå:<br />
E<br />
y<br />
x<br />
= x<br />
y<br />
y ′ . (8.1.1)<br />
Íà ïðàêòèö³ ³ñíóþòü òàêîæ ³ òàê³ çàäà÷³:<br />
1. Äëÿ çàäàíî¿ øâèäêîñò³ v(t) ìàòåð³àëüíî¿ òî÷êè òðåáà<br />
çíàéòè ïðîéäåíèé íåþ øëÿõ S = S(t).<br />
2. Çà â³äîìèì êóòîâèì êîåô³ö³ºíòîì k(x) =f′(x) òðåáà<br />
çíàéòè êðèâó, ÿêà çàäàíà ð³âíÿííÿì ó = f(x).<br />
3. ³äîìî, ùî åëàñòè÷í³ñòü ôóíêö³¿ f(x) äîð³âíþº ϕ(x).<br />
Òðåáà çíàéòè ñàìó ôóíêö³þ f(x).<br />
Çàóâàæåííÿ. Çàäà÷³ 1 – 2 êëàñè÷í³ ³ ìàéæå â êîæíîìó<br />
ó÷áîâîìó ïîñ³áíèêó ç êóðñó âèùî¿ ìàòåìàòèêè âîíè íàâîäÿòüñÿ.<br />
Ùîäî çàäà÷³ 3, òî âîíà, ìîæëèâî, ïîñòàâëåíà âïåðøå.<br />
Ïðèêëàä 8.1.1. Çíàéòè ôóíêö³þ, åëàñòè÷í³ñòü ÿêî¿ äîð³âíþº<br />
α(α = ñonst).<br />
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