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Derivacije(III)<br />

Zadatak 1. Odredite prvu derivaciju sljedećih funkcija:<br />

(a) y = √ 4 − √ 4 + x<br />

Rj: y ′ =<br />

−1<br />

4 √ 4 − √ 4 + x √ 4 + x<br />

(b) y = √ 2x + 7<br />

Rj: y ′ =<br />

1<br />

√ 2x + 7<br />

(c) y = √ (x 2 − x + 1) 5<br />

Rj: y ′ = 5 2 (2x − 1)√ (x 2 − x + 1) 3<br />

(d) y = (4x 2 − 3) 2 (x + 5) 3<br />

Rj: y ′ = (4x 2 − 3)(x + 5) 2 (28x 2 + 80x − 9)<br />

(e) y = (x 3 − 2x 2 + 7x − 3) 4<br />

Rj: y ′ = 4(3x 2 − 4x + 7)(x 3 − 2x 2 + 7x − 3) 3<br />

√<br />

4<br />

(f) y =<br />

x − √ 3x<br />

√<br />

3x + 2<br />

Rj: −<br />

2x 3 2<br />

(g) y = 1 − 3√ 2x<br />

1 + 3√ 2x<br />

Rj: y ′ =<br />

(h) y = ctg 2 x<br />

Rj: − 2ctgx<br />

sin 2 x<br />

−4<br />

3(1 + 3√ 2x) 2 3√ 4x 2


(i) y = sin(sin t)<br />

Rj: y ′ = cos(sin t) · cos t<br />

(j) y = e 2x+3 (x 2 − x + 1 2 )<br />

Rj: y ′ = 2x 2 e 2x+3<br />

(k) y = log 3 (x 2 − sin x)<br />

Rj: y ′ =<br />

2x − cos x<br />

(x 2 − sin x) ln 3<br />

(l) y = arcsin √ sin x<br />

Rj: y ′ =<br />

cos x<br />

2 √ sin x − sin 2 x<br />

(m) y = 1 4 ln 1 + x<br />

1 − x − 1 2 arctgx<br />

x2<br />

Rj: y ′ =<br />

1 − x 4<br />

(n) y = √ 1<br />

√<br />

3x<br />

arctg 3 1 − x 2<br />

Rj: y ′ =<br />

1 + x2<br />

1 + x 2 + x 4<br />

(o) y = arccos √ 1 − 3x<br />

Rj: y ′ 3<br />

=<br />

2 √ 3x − 9x 2

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