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ÐеждÑнаÑÐ¾Ð´Ð½Ð°Ñ ÐºÐ¾Ð½ÑеÑенÑÐ¸Ñ ÑÑÑденÑов, аÑпиÑанÑов и молодÑÑ ...
ÐеждÑнаÑÐ¾Ð´Ð½Ð°Ñ ÐºÐ¾Ð½ÑеÑенÑÐ¸Ñ ÑÑÑденÑов, аÑпиÑанÑов и молодÑÑ ...
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28<br />
EHFHGHKH@<br />
< wlhc jZ[hl_ ihdZaZgh dZdbf h[jZahf ih^h[gu_ khhlghr_gby \ nhjfZebaf_<br />
[hj_e_\kdbo ijZ\be kmff ijb\h^yl d k\yab f_`^m f_ahg- [Zjbhggufb dhgklZglZfb<br />
g(ηΣ 0 Σ 0 bJη,Λ,Λ) .<br />
Ihykgbfhkgh\gmxb^_xgZijbf_j_68Fh`ghihdZaZlvqlh\SUdhg<br />
klZglu k\yab ^ey Σ-ih^h[guo [Zjbhgh\ %TTK k ^\mfy d\ZjdZfb h^gh]h ZjhfZlZ \<br />
kbff_ljbqghfkhklhygbbkg_cljZevgufbf_ahgZfb0 ^π 0 , η`hij_^_eyxlky\ujZ<br />
`_gb_f<br />
g(MBB)=g Mqq 2F+g Mhh (F-D),<br />
]^_Fb'-oZjZdl_jgu_dhgklZgluSUZagZq_gbydhgklZglk\yabf_ahgh\kd\ZjdZfb<br />
hij_^_eyxlkybanhjfmeulhdh\<br />
j (π 0 )=√(1/2) (u γ 5 u - d γ 5 d), j(η)=√(1/6) (u γ 5 u + d γ 5 d - 2 s γ 5 s).<br />
GZihfgbfj_amevlZl68-g(ηΣ 0 Σ 0 ) = √(2/3)D, g(ηΛΛ) = -√(2/3)D.<br />
AZibr_f\ujZ`_gb_^eydhgklZgluJηΣ 0 Σ 0 \\b^_<br />
g(ηΣ 0 Σ 0 ) = g ηuu F+g ηdd F+g ηss (F-D) = -g ηss D =√(2/3)D.<br />
L_i_jv aZibr_f nhjfZevgu_ \ujZ`_gby dhlhju_ ihemqZxlky ba \ur_ijb\_<br />
^_ggh]h\ujZ`_gbyaZf_gZfbX⇔ s)<br />
g(ηΣ 0 usΣ 0 us) = -g ηuu D=-√(1/6)D<br />
b (d ⇔ s)<br />
g(ηΣ 0 dsΣ 0 ds) = -g ηdd D=-√(1/6)D<br />
KijZ\_^eb\hke_^mxs__lh`^_kl\h<br />
2 g(ηΣ 0 usΣ 0 us)+2 g(ηΣ 0 dsΣ 0 ds) - g(ηΣ 0 Σ 0 ) = 3g(ηΛΛ)<br />
Wlhlh`^_kl\hke_^m_lbak\yab\hegh\uonmgdpbcΣ 0 bΛ[Zjbhgh\b\kihfh]Z<br />
l_evguo]bi_jhgh\Σ 0 usbΣ 0 dsBlZdgZijbf_j_fh^_ebmgblZjghckbff_ljbbfuihdZ<br />
aZebdZdbfh[jZahfhlijZ\eyykvhl\ujZ`_gby^eyΣ 0 fh`ghihemqblv\ujZ`_gb_^ey<br />
Λ.<br />
HdZau\Z_lky qlh ZgZeh]bqgu_ khhlghr_gby bf_xl f_klh b \ kemqZ_ [hj_e_\<br />
kdboijZ\bekmff^eyiheyjbaZpbhgguohi_jZlhjh\Π(Σ 0 bΠ(Λhij_^_e_gguolZd`_<br />
dZd\>@Fh`ghihdZaZlvqlh^eygbokijZ\_^eb\ukhhlghr_gby<br />
2 Π(Σ 0 us) + 2 Π(Σ 0 ds) – Π(Σ 0 )= 3 Π(Λ).<br />
]<br />
b khojZgyy g_\ujh`^_ggufb \k_ fZkku d\Zjdh\ b bo dhg^_gkZlu ihemqbf ijZ\beh<br />
kmff\uibr_f_]ha^_kvlhevdh^eyh^ghcbaehj_gp_\kdbokljmdlmj^eydhgklZglu<br />
k\yabΣ 0 :<br />
√(1/2) m 2 η λ 2 Σ g(ηΣ 0 Σ 0 ) exp(-m 2 Σ /M 2 ) [1+A Σ M 2 ] =<br />
= m 2 η M 4 E0(x) [g ηss /12/π 2 /f η +3f 3η /4/f η /√(2)-M 2 /f η [g ηss [m d +<br />
m u ]- m 2 η /72/ f η [g ηss ]<br />
+ m 2 0 /6/ f η [ (g ηuu m d +g ηdd m u )] ≡ D(u,d,s)<br />
28