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:
∂u
= 0
∂n
∂Ω
(2)
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u ∈ L 2(
Ω )
(3)
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q( x,
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x
1
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= 0
σi
⎣∂n⎦
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∂u
∂x
∂u
∂x
x=
x
x=
x
∂u
∂n
2
− ∆u = k q(
x,
y)
u
(4)
∂u
= 0,
∂n
y= 0
y= 1
∑ ∞
= 1
= 0
= 2 γ
n
( u,cos(
πny))
2 1
1
n
∑ ∞
= 1
= −2 γ
n
( u,
cos( πny))
2 2
2
n
( u,1)
L 2(
S i
)
= 0, i = 1, 2
L ( S )
cos( πny)
L ( S )
cos( πny)
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(k)