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Separácia koreňov a určenie počiatočnej aproximácie<br />

Príklad: Zí<strong>sk</strong>ajme hrubý odhad koreňov rovnice<br />

x<br />

e<br />

2<br />

+ x − 3=<br />

0<br />

Riešenie: Zadanú funkciu upravíme na tvar<br />

x<br />

e<br />

= 3−x<br />

2

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