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ZGINANIE PROSTE-zad

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9. <strong>ZGINANIE</strong> <strong>PROSTE</strong><br />

Zadanie 9.1<br />

Belka swobodnie podparta na dwóch podporach A i B, obciążona jest na końcu siłą P.<br />

Sprawdź wytrzymałość belki, jeśli dopuszczalne naprężenia przy zginaniu kg=1200[kG/cm 2 ].<br />

Dane: P=800[kG], a=20[cm], l=100[cm]. Pominąć wpływ sił wewnętrznych.<br />

∑<br />

∑<br />

R<br />

F<br />

M<br />

= R<br />

= −P<br />

+ R<br />

( a + l)<br />

− Pa − Pl − R l = 0<br />

A<br />

iy<br />

iB<br />

A<br />

A<br />

Pa<br />

= − − P<br />

l<br />

B<br />

+ P = 0<br />

− R<br />

A<br />

l<br />

Pa<br />

− − P + P + RB<br />

l<br />

Pa<br />

RB<br />

=<br />

l<br />

= 0


0 < X 1 < a 0 < X 2 < l<br />

Mg 1 =Px 1 Mg 2 =R By x 2<br />

M = Pa = 800⋅<br />

20 16000<br />

max =<br />

∑<br />

∑<br />

[ kGcm]<br />

S ⋅ yi<br />

20⋅80⋅0<br />

+ 40⋅<br />

20⋅30<br />

24000<br />

yc =<br />

= = 10<br />

S 20⋅80<br />

+ 40⋅<br />

20 240<br />

[ mm]<br />

I<br />

I<br />

z<br />

z<br />

bh<br />

=<br />

3<br />

3<br />

20⋅<br />

40<br />

=<br />

3<br />

3<br />

80⋅<br />

20<br />

+<br />

3<br />

3<br />

= 640000<br />

4<br />

[ mm ]<br />

W<br />

I<br />

y<br />

z<br />

z<br />

= =<br />

o<br />

640000<br />

16000<br />

40<br />

3<br />

[ mm ]<br />

M max 16000 ⎡ kG ⎤<br />

σ max = = = 1000<br />

⎢ 2<br />

W 16 ⎣cm<br />

⎥<br />

⎦<br />

z<br />

σ max<br />

= 1000 〈 1200 = kg

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