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1. Funkcije kompleksne varijable f : C → C f(z) = w = f(x + iy) = u(x, y ...

1. Funkcije kompleksne varijable f : C → C f(z) = w = f(x + iy) = u(x, y ...

1. Funkcije kompleksne varijable f : C → C f(z) = w = f(x + iy) = u(x, y ...

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3<br />

2. Limes niza i funkcije <strong>kompleksne</strong> <strong>varijable</strong>.<br />

Neprekidnost funkcije <strong>kompleksne</strong> <strong>varijable</strong><br />

Definicija <strong>1.</strong> Za niz kompleksnih brojeva (z n ) kažemo da konvergira<br />

kompleksnom broju a ako<br />

(∀ɛ > 0)(∃n z ∈ N) n > n z ⇒ |z n − a| < ɛ<br />

Tada a zovemo limes niza (z n ) i pišemo a = lim<br />

n→∞<br />

z n .<br />

Teorem <strong>1.</strong> Niz kompleksnih brojeva (z n ), z n = x n + <strong>iy</strong> n , konvergira<br />

kompleksnom broju a = α + iβ ako i samo ako niz (x n ) konvergira ka<br />

α i niz (y n ) konvergira ka β;<br />

z n = x n + <strong>iy</strong> n , a = α + iβ : z n → a ⇔ x n → α i y n → β.<br />

Ako je z n zadan u polarnom obliku, z n = ρ n e iφn ,<br />

lim ρ }<br />

n = ρ 0<br />

n→∞<br />

lim φ ⇔ lim z<br />

n = φ n = ρ 0 e iφ 0<br />

0 n→∞<br />

n→∞<br />

Definicija 2.<br />

A = lim<br />

z→z0<br />

f(z) ⇔ (∀ɛ > 0)(∃δ > 0) |z − z 0 | < δ ⇒ |f(z) − f(z 0 )| < ɛ.<br />

Teorem 2.<br />

f(z) = u(x, y)+iv(x, y), z 0 = x 0 +<strong>iy</strong> 0<br />

Teorem 3.<br />

lim f(z) = A i lim g(z) = B ⇒<br />

z→z 0 z→z0<br />

⇒ lim f(z) = lim<br />

z→z0 x→x0<br />

u(x, y)+i<br />

x→x0<br />

lim v(x, y).<br />

y→y 0 y→y 0<br />

lim<br />

z→z 0<br />

(f(z) ± g(z)) = A ± B,<br />

lim<br />

z→z 0<br />

(f(z) · g(z)) = A · B,<br />

f(z)<br />

lim<br />

z→z 0 g(z) = A , g(z) ≠ 0, B ≠ 0.<br />

B<br />

Definicija 3. Za funkciju f(z) kažemo da je neprekidna u točki z 0 ako<br />

(∀ɛ > 0)(∃δ > 0) |z − z 0 | < δ ⇒ |f(z) − f(z 0 )| < ɛ, ∀z ∈ D f .<br />

Funkcija f(z) = u(x, y) + iv(x, y) je neprekidna u točki z 0 = x 0 + <strong>iy</strong> 0<br />

ako i samo ako su u(x, y) i v(x, y) neprekidne u (x 0 , y 0 ).<br />

Funkcija f(z) je neprekidna u z 0 ako je lim<br />

z→z0<br />

f(z) = f(z 0 ).

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