1 Termodinamika és optika gyakorlat II. éves fizikushallgatók ...

§
∂T
∂p
¥ ¥
−SdT + V
dp
§
∂U
∂p
T
= T ∂S
∂p
T
∂T
∂p
S
= −
− p ∂V
∂p
T
∂S
∂p
T
∂S
∂T p
∂U
∂p
S
=
T
=?
∂V
∂T p
Cp/T
=?
= −T ∂V
∂T
−SdT + V dp
§
T0
∂V
∂T
p
V = a1 − a2p + a3p 2 ,
p
= a4 + a5p,
a1, a2, a3, a4, ¥
a5
W ∆U
T V α
= .
Cp
+ pV κT = −T V α + pV κT .
T0
DW = −pdV = −p(−a2dp + 2a3pdp)
p2
W = −
p1
−a2p + 2a3p 2 dp = a2
∆U = Q + W T0
Q =
p2
p2
T0dS = T0
∂S
∂p
dp = −T0
p1
= −T0
p1
a4 (p2 − p1) + a5
∆U = p2 1 − p 2 2
2
T
p2 1 − p2
2
.
2
p2
p 2 2 − p 2 1
2
p1
∂V
∂T
p
− 2
3 a3
3
p2 − p 3 1 .
dp = −T0
p2
(a2 − a5T0) − 2
3 a3
3
p2 − p 3 1 − a4T0 (p2 − p1) .
p1
p1 p2
(a4 + a5p) dp