1 Termodinamika és optika gyakorlat II. éves fizikushallgatók ...
1 Termodinamika és optika gyakorlat II. éves fizikushallgatók ... 1 Termodinamika és optika gyakorlat II. éves fizikushallgatók ...
¥ pV = nRT p0 − αV 2 V = nRT p0V − αV 3 = nRT p0 ∂V ∂T α ∂V ∂T 2 ∂V − 3αV ∂T α = nR ∂ ∂T α p0 − 3αV 2 Cα = CV + p0 − αV 2 α = nR nR p0 − 3αV 2 p/V = const Cx = Cp+Cv ¥ 2 T (V ) = p0 − αV 2 V = nRT T (V ∗ ) = max. p0 − αV 2 V nR = p0 − αV 3 nR dT (V ) dV = 0 = p0 − 3αV 2 nR V ∗ = Tmax = T (V ∗ ) = p0 p0 3α p0 3α p0 p0 − α 3α 3α nR = 2p0 p0 3nR 3α
§ £ £ p + an2 V 2 (V − bn) = nRT U = cV mT − n2 a V 0 = DQ = dU + pdV ¥ p = nRT V −bn m/n = M ¥ an2 − V 2 0 = DQ = cV mdT + n2 a nRT an2 dV + − V 2 V − bn V 2 dV 0 = cV mdT + nRT V − bn dV cV m nR dT = − T V − bn dV cV ln T + const1 = − R ln (V − bn) + const2 M ln T cV + ln (V − bn) R/M = const3 T cV (V − bn) R/M = const
- Page 1: ¡£¢¥¤§¦©¨¦©¨¨¤ ¥¢¦
- Page 5 and 6: p 1 2 V1 ¥ izoterma T 2 adiabata
- Page 7 and 8: § − 1 ∂ V ∂V ∂T p ∂
- Page 9 and 10: § ∂T ∂p ¥ ¥ −SdT + V
- Page 11 and 12: Cp T ∂ (S, p) ∂ (S, p) ∂ (T,
- Page 13 and 14: § ¥ M = C CH − CM χT = 1
- Page 15 and 16: ¨¤ § ¥§ ¥ r £ d n >
- Page 17 and 18: § θB sin θh = η = 1.28 s
- Page 19 and 20: ¥ r n λn = λ/n § ∆
- Page 21 and 22: ¥ 1 2π 2π e 0 −ix cos φ d
- Page 23 and 24: d n ′ nθ = nθ y ′ d y = y
- Page 25: TR1 = 1 0 1 , Td = 1 d n 0 1 ,
§<br />
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£<br />
<br />
<br />
<br />
£<br />
<br />
<br />
<br />
p + an2<br />
V 2<br />
<br />
(V − bn) = nRT<br />
U = cV mT − n2 a<br />
V<br />
0 = DQ = dU + pdV<br />
¥ p = nRT<br />
V −bn<br />
<br />
m/n = M ¥<br />
<br />
an2 − V 2<br />
<br />
0 = DQ = cV mdT + n2 <br />
a nRT an2<br />
dV + −<br />
V 2 V − bn V 2<br />
<br />
dV<br />
0 = cV mdT + nRT<br />
V − bn dV<br />
cV m nR<br />
dT = −<br />
T V − bn dV<br />
cV ln T + const1 = − R<br />
ln (V − bn) + const2<br />
M<br />
ln T cV + ln (V − bn) R/M = const3<br />
T cV (V − bn) R/M = const
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