1 Termodinamika és optika gyakorlat II. éves fizikushallgatók ...

1 Termodinamika és optika gyakorlat II. éves fizikushallgatók ... 1 Termodinamika és optika gyakorlat II. éves fizikushallgatók ...

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k k(α1) = h tg[β(α1)] − tg[β(α0)] tg(α1) − tg(α0) k = lim [k(α1)] = lim h α1→α0 α1→α0 tg[β(α1)] − tg[β(α0)] tg(α1) − tg(α0) ¥ α1 → α0 ′ (tg ◦ β) = h tg ′ = (α0) = h (cos −2 ◦β) · cos 2 ·β ′ (α0) = h cos2 (α0) cos 2 [β(α0)] β′ (α0) β β(α) = arcsin[sin(α)/n] ′ β (α0) cos2 [β(α0)] β ′ = arcsin ◦ sin ′ = n 1 1 − sin n cos 2 ◦β = 1 − sin 2 ◦β = 1 − sin 2 ◦ arcsin ◦ sin n · 2 1/2 1 · cos = n = 1 − cos n2 2 − sin , 1/2 2 sin n = n2 − sin 2 n2 . k k = h n 2 cos 3 (α0) [n2 − sin 2 . (α0)] 3/2 ¨¤ § ¥ n R λ R r d(r)

¥ r n λn = λ/n § ∆φ(r) = 2d(r) 2π λn − π = 4πd(r)n λ £ d(r) ¥ 2π ∆φ(r) = 2πm d(r) d(r) = (2m + 1)λ . 4n − π, √ d(r) = R − R2 − r2 R − R2 − r2 (2m + 1)λ = . 4n rm = 2m + 1 λR − 2n 2m + 1 4n π 2 λ2 2m + 1 ≈ 2n λR, R ≫ λ ¥¥ ¨¤ § λ ¥ P ¥ R2 UFresnel(L) = C eikL L S R1 P r2 ik U(r)e 2L d 2 r, k = 2π/λ C = k/(2πi) L S U(r) r IFresnel(L) = |UFresnel(L)| 2

¥ <br />

r <br />

n<br />

λn = λ/n §<br />

<br />

∆φ(r) = 2d(r) 2π<br />

λn<br />

− π = 4πd(r)n<br />

λ<br />

£<br />

d(r) ¥<br />

<br />

2π ∆φ(r) = 2πm<br />

d(r) <br />

d(r) =<br />

(2m + 1)λ<br />

.<br />

4n<br />

− π,<br />

√ <br />

d(r) = R − R2 − r2 R − R2 − r2 (2m + 1)λ<br />

= .<br />

4n<br />

<br />

<br />

<br />

rm =<br />

<br />

2m + 1<br />

λR −<br />

2n<br />

2m + 1<br />

4n<br />

π<br />

2 λ2 <br />

2m + 1<br />

≈<br />

2n λR,<br />

<br />

R ≫ λ<br />

¥¥<br />

<br />

<br />

<br />

¨¤<br />

<br />

§<br />

<br />

λ<br />

<br />

¥<br />

<br />

P<br />

<br />

¥<br />

R2<br />

UFresnel(L) = C eikL<br />

L<br />

<br />

<br />

S<br />

R1<br />

P<br />

r2 ik<br />

U(r)e 2L d 2 r,<br />

<br />

k = 2π/λ C = k/(2πi) L S U(r)<br />

r IFresnel(L) = |UFresnel(L)| 2

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