1 Termodinamika és optika gyakorlat II. éves fizikushallgatók ...
1 Termodinamika és optika gyakorlat II. éves fizikushallgatók ... 1 Termodinamika és optika gyakorlat II. éves fizikushallgatók ...
§ ¥ ¥ H → 0 C0 = B/T 2 B ¥ T1 H1 H2 < H1 ¥ U M CM = ∂U (M, T ) ∂T H M CH = CM + µ0CV H 2 ¥ dT = µ0CV H CH T 2 = ∂U (T ) 1 dH = T T ∂T = C0. = B + µ0CV H2 T 2 . µ0CV H dH. B + µ0CV H2 T (H) dT T = H dH. B/ (µ0CV ) + H2 T2 < T1 x a 2 +x 2 = 1 2 ln a 2 + x 2 T2 = T1 B + µ0CV H2 2 B + µ0CV H2 . 1 H2 < H1 B ≪ µ0CV H2 2 H1 T2 ≈ T1 H2
¨¤ § ¥§ ¥ r £ d n > 1 θ r § sin θ = r r+d r 1 > r + d n , r > d n − 1 d sin θ > 1/n § z n(z) z θ(z) § ¥ z0 θ(z0) n ∝ √ ρ ρ § z0 z0 +∆z § ∆θ z0 z0+∆z0 R(z0) = | lim∆z→0(∆l/∆θ)| ∆l z0 ∆l R(z0) = lim ∆z ∆l 1 ∆z→0 ∆z ∆θ = lim ∆z→0 ∆z |θ ′ (z0)| . lim ∆z→0 ∆l = ∆z 1 cos[θ(z0)] .
- Page 1 and 2: ¡£¢¥¤§¦©¨¦©¨¨¤ ¥¢¦
- Page 3 and 4: § £ £ p + an2 V 2 (V −
- Page 5 and 6: p 1 2 V1 ¥ izoterma T 2 adiabata
- Page 7 and 8: § − 1 ∂ V ∂V ∂T p ∂
- Page 9 and 10: § ∂T ∂p ¥ ¥ −SdT + V
- Page 11 and 12: Cp T ∂ (S, p) ∂ (S, p) ∂ (T,
- Page 13: § ¥ M = C CH − CM χT = 1
- Page 17 and 18: § θB sin θh = η = 1.28 s
- Page 19 and 20: ¥ r n λn = λ/n § ∆
- Page 21 and 22: ¥ 1 2π 2π e 0 −ix cos φ d
- Page 23 and 24: d n ′ nθ = nθ y ′ d y = y
- Page 25: TR1 = 1 0 1 , Td = 1 d n 0 1 ,
¨¤<br />
<br />
§<br />
<br />
¥§<br />
¥<br />
r £ d<br />
n > 1<br />
<br />
θ<br />
r<br />
<br />
§<br />
<br />
sin θ = r<br />
r+d<br />
<br />
<br />
<br />
<br />
r 1<br />
><br />
r + d n , r > d<br />
n − 1<br />
d<br />
<br />
sin θ > 1/n <br />
§<br />
<br />
z n(z)<br />
z θ(z)<br />
§ <br />
¥<br />
z0<br />
θ(z0)<br />
n ∝ √ ρ ρ <br />
<br />
§<br />
z0<br />
<br />
<br />
<br />
z0 +∆z §<br />
<br />
∆θ z0 z0+∆z0<br />
R(z0) = | lim∆z→0(∆l/∆θ)| ∆l z0<br />
<br />
<br />
∆l <br />
R(z0) = lim <br />
∆z <br />
<br />
∆l 1<br />
∆z→0 ∆z ∆θ = lim<br />
∆z→0 ∆z |θ ′ (z0)| .<br />
<br />
lim<br />
∆z→0<br />
<br />
∆l<br />
=<br />
∆z<br />
1<br />
cos[θ(z0)] .
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