1 Termodinamika és optika gyakorlat II. éves fizikushallgatók ...

1 Termodinamika és optika gyakorlat II. éves fizikushallgatók ... 1 Termodinamika és optika gyakorlat II. éves fizikushallgatók ...

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∂V ∂T S ∂V ∂T p = − ∂S ∂T | V ∂S ∂V | T V α = − CV T V α = − CV T V α 1 − ∂V ∂T p ∂S ∂V ∂V ∂p 1 T T = − CV T V α = CV T V α ¥ − CV κT CV = − T V α2 Cp − CV ¨¤ 1 ∂p ∂T V 1 V α (−V κT ) = − CV κT . T V α2 = 1 1 − γ . ¥ M = f(H, T ), dU = T dS + µ0HdM, f ££ H M M H M H £ ¥ ¥ M ←→ V, µ0H ←→ −p. § CH T ∂ (S, H) ∂ (S, H) = = ∂ (T, H) ∂ (T, M) = CM T + µ0 ∂H ∂T M CH − CM = µ0T χT V χT = 1 V ∂ (T, M) ∂ (T, H) = 2 ∂M ∂H T , ∂S ∂M ∂H ∂M ∂H ∂S ∂T = µ0 T ∂T M ∂H ∂T T M ∂H ∂T . M M ∂H ∂M 2 , T − ∂S ∂M T ∂H ∂T M ∂M ∂H ¥ H χT > 0 χT < 0 T

§ ¥ M = C CH − CM χT = 1 V CH − CM = µ0T C T ∂H ∂T M CV H T , ∂M ∂H T = M CV . = C T . 2 M V C2 M = µ0 V 2 2 CV § M = V f H T ¥ U M T dU = T dS + µ0HdM ∂U = T ∂M ∂S ∂M T T + µ0H = −µ0 ∂ (H/T ) ∂T M = 1 T ∂H ∂T ∂H ∂T M M = µ0 = −µ0T − H T 2 CV H2 T 2 . 2 ∂ (H/T ) ∂T M = const. f(H/T ) = const H/T = const. ∂U ∂M § dH ¥ DQ = T dS = 0 0 = dS = ∂S ∂T ¥ H dT = − µ0T CH T dT + ∂S ∂H ∂M ∂T H T = 0. dH = CH T dH = µ0CV H CH ¥ CV H M = T H T + µ0 ∂M ∂T 1 T dH. H . M .

§<br />

¥<br />

M =<br />

C CH − CM<br />

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<br />

χT = 1<br />

V<br />

CH − CM = µ0T C<br />

T<br />

∂H<br />

∂T<br />

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M<br />

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= C<br />

T .<br />

2 M<br />

V<br />

C2 M<br />

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V 2 2<br />

CV<br />

§<br />

<br />

M = V f<br />

<br />

H<br />

T<br />

¥ <br />

U M T<br />

<br />

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dU = T dS + µ0HdM <br />

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∂U <br />

= T<br />

∂M<br />

∂S<br />

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T<br />

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∂ (H/T )<br />

∂T<br />

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M<br />

= 1<br />

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∂T<br />

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M<br />

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T 2<br />

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2 ∂ (H/T )<br />

∂T<br />

<br />

M = const. f(H/T ) = const H/T = const.<br />

<br />

<br />

∂U <br />

<br />

∂M<br />

§<br />

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dH<br />

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DQ = T dS = 0<br />

0 = dS = ∂S<br />

<br />

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∂T<br />

¥<br />

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dH = CH<br />

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<br />

H<br />

.<br />

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