·Is-enerji Denklemi (Kinetik S¬nav¬-17-3) Problem : Sekil 1 deki yay ...
·Is-enerji Denklemi (Kinetik S¬nav¬-17-3) Problem : Sekil 1 deki yay ...
·Is-enerji Denklemi (Kinetik S¬nav¬-17-3) Problem : Sekil 1 deki yay ...
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<strong>Problem</strong> :<br />
·I¸s-<strong>enerji</strong> <strong>Denklemi</strong><br />
(<strong>Kinetik</strong> <strong>S¬nav¬</strong>-<strong>17</strong>-3)<br />
Figure 1:<br />
¸<strong>Sekil</strong> 1 <strong>deki</strong> <strong>yay</strong> 625 mm lik deforme olmam¬¸s boya sahip olup sistem durgun halden<br />
serbest b¬rak¬l¬yor. a) Kürenin dü¸sey olarak 250 mm yerde¼gi¸stirdi¼gi an, b) L ¸seklin<strong>deki</strong><br />
kol 35 ± döndü¼gü an kürenin h¬z¬n¬ bulunuz.<br />
Çözüm :<br />
a) Sistem için i¸s <strong>enerji</strong> denklemi<br />
U 0 12 =¢T +¢Vg +¢Ve<br />
= 0 d¬r, kinetik <strong>enerji</strong> de¼gi¸simi<br />
¢T = m ¡<br />
2 v2 ¡v<br />
2<br />
2 ¢<br />
2<br />
1 =2v2 gravitasyonel potansiyel <strong>enerji</strong> de¼gi¸simi<br />
d¬¸s kuvvet tesir etmemektedir, dolay¬s¬ylaU 0 12<br />
¢V g = mg(h 2 ¡h 1) = ¡4(9:81)0:25<br />
¢Vg = ¡9:81 j<br />
elastik potansiyel <strong>enerji</strong> de¼gi¸simi<br />
¢Ve = k ¡ 2 x2 ¡x<br />
2<br />
2¢ 1<br />
deforme olmam¬¸s <strong>yay</strong> boyux0 = 0:625 m dir,<br />
x1 = AB ¡x0 =<br />
OA 1 = OA 2 = p 0:6 2 +0:25 2 = 0:65 m<br />
q<br />
0:6 2 +(0:65 ¡0:25) 2 ¡0:625 = 0:0961 m<br />
Dr. M. Kemal Apalak 1
Figure 2:<br />
A2B = p 0:652 +0:652 =0:9192 m<br />
x2 = A2B ¡x0 = 0:9192 ¡0:625<br />
x2 = 0:2942 m<br />
¢Ve = 210 ¡ 2 2<br />
0:2942 ¡0:0961<br />
2<br />
¢<br />
¢Ve = 8:1184 j<br />
b) Sistem için i¸s <strong>enerji</strong> denklemi<br />
U 0 12 = ¢T +¢Vg +¢Ve<br />
0 = 2v 2 2 ¡9:81+8:1184<br />
v2 = 0:9197 m/s<br />
U 0 12 = ¢T +¢Vg +¢Ve =0<br />
kinetik <strong>enerji</strong> de¼gi¸simi<br />
¢T = m ¡ 2<br />
v2 ¡v<br />
2<br />
2¢ 2<br />
1 =2v2 gravitasyonel potansiyel <strong>enerji</strong> de¼gi¸simi<br />
¢Vg =mg¢h<br />
OB = OA =0:65 µ m<br />
250<br />
® = arctan =22:62<br />
600<br />
±<br />
¯ = 35 ¡22:62 = 12:38 ±<br />
h = OA2sin¯ +0:25 = 0:65sin12:38+0:25<br />
h = 0:3894 m<br />
Dr. M. Kemal Apalak 2
elastik potansiyel <strong>enerji</strong> de¼gi¸simi<br />
bulunur.<br />
35 o<br />
Figure 3:<br />
¢Vg = ¡mgh = ¡4(9:81)0:3894<br />
¢V g = ¡15:28 j<br />
¢Ve = k ¡<br />
2 x2 ¡x<br />
2<br />
2 ¢<br />
1<br />
BA2 = p 0:652 +0:652 ¡2(0:65)0:65cos(90 +12:38)<br />
BA2 = 1:013 m<br />
x2 = BA2 ¡x0 =1:013 ¡0:625 = 0:3879 m<br />
x1 = 0:0961 m<br />
¢Ve = 210 ¡ 2 2<br />
0:3879 ¡0:0961<br />
2<br />
¢<br />
¢Ve = 14:837 j<br />
0 = ¢T +¢Vg +¢Ve<br />
0 = 2v 2 2 ¡15:28+14:837<br />
v 2 = 0:471 m/s<br />
Dr. M. Kemal Apalak 3