ExamView - 2Dmotion7.tst
ExamView - 2Dmotion7.tst
ExamView - 2Dmotion7.tst
- No tags were found...
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
Santa to the Sea is a nonprofit event borne out of a desire to give back to the community. Whatstarted in 2003 as a toy drive to celebrate the relocation of the world’s largest Santa Claus fromCarpinteria to Oxnard, has grown into a robust running event, toy drive, and communityfundraiser. Santa to the Sea includes a sanctioned half marathon and a 2-person half marathonrelay, plus 5K run and 1K kids fun runs. The Santa to the Sea Scholarship Fund partners withthe Oxnard College Foundation to award $500 scholarships to local high school students andadults continuing their education at Oxnard College.###
han hälsan.n,Age börJade att funclera över vacl so.r'i kuncLe yaraorsaken t i11 att h;rn nrådde i1la i boe taden. l,le ttran så srnånlngom konr I'ranr t111, att clet finnsstrålnlng runt om krlng oss, som har olika polarife t . l"ör hans de 1 . ska clenna s trå1ning varaposiötV.t laddad. Om så inte är faf tet äq detnödvändigt att man ändrar polariteten. Ilans för'edragvar mycket lntressant. uet förde 'oniikllgetrtankarna t111 det universlella perspektlvet.r\lltså att vi på jorden inte är en isolerad delårv universurn utan al-1t hätrger 'aamnlail . !'öre1äs =nlngen var ruyck-et I'ärrgslandeLördagen ägnades åt, efter frukosten var avklarad,.att undersöka närmas.te omgivnirrgen I)å förekomst av va.t tenådror och eventuella jords trötumar.Vi f'lck bl a av Yngve i uppdrag att kartlägga1'örekoms ten av vat tens trörnrnar runt ett par s törreträd. tJllden av clessa blev så småninSom' gansl
ID: AProjectiles and Stuff TestAnswer SectionMULTIPLE CHOICE1. ANS: D PTS: 1 DIF: easy REF: K/U2. ANS: B PTS: 1 DIF: easy REF: K/U3. ANS: D PTS: 1 DIF: average REF: K/U4. ANS: A PTS: 1 DIF: easy REF: K/U5. ANS: B PTS: 16. ANS: C PTS: 17. ANS: A PTS: 18. ANS: C PTS: 19. ANS: A PTS: 110. ANS: B PTS: 111. ANS: B PTS: 112. ANS: C PTS: 113. ANS: D PTS: 1PROBLEM14. ANS:v x= 18.1cos(22.5°)v x= 16.7 m / sv y= 18.1sin22.5°v y= 6.9 m / shorizontal:d x= v xtt = d xv xt = 16.516.7t = 0.99svertical:d y= v yit + 0.5a yt 2d y= 6.9(0.99) + 0.5(−9.8)(0.99) 2d y= 2.0 mSince the ball is below the top of the net, the player scored!PTS: 11 of 3
ID: A15. ANS:a) F = kx(1.2)(9.8) = k(0.052)k = 226 N / mT = 2πT = 2πT = 0.46 smk1.2226b) Since the maximum speed occurs at equilibrium, where all of the energy is kinetic,E i= E f0.5kx 2 = 0.5mv 2kx 2 = mv 2226(0.042) 2 = 1.2v 2v = 0.58 m / sc) E i= E f0.5kx 2 i= 0.5kx 2 f+ 0.5mv 2226(0.042) 2 = 226x 2 + 1.2(0.312) 2x = 0.035mPTS: 12 of 3
ID: A16. ANS:⎯a) p →b)⎯g + p→= p ⎯ →′rp rtp g17.3 opt'c) p′ t= m tv′ tp g= p′ tsin17.3p r= p′ tcos 17.3p′ t= (8000)(16.4)p g= (131200) sin17.3p r= (131200) cos 17.3p′ t= 131200kgm / sp g= 39000 kgm / sp r= 125300 kgm / sp g= m gv gp r= m rv r39000 = 3000v gv g= 13 m / s125300 = 5000v rv r= 25 m / sSince the speed limit was 50.0 km/h (13.9 m/s), the red truck was speeding.PTS: 1SHORT ANSWER17. ANS:Yes. The slower the horizontal speed, the longer it will take the ball to get there. The longer it takes to getthere, the more time it has to fall; therefore, it will fall a greater distance.PTS: 13 of 3