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Ovan ⇒<br />

⇒<br />

⎡<br />

B e = 1 ⎣<br />

2A α<br />

DB e =<br />

K e =<br />

⎡<br />

E ⎣<br />

6A α<br />

⎡<br />

Et<br />

12A α ⎢<br />

⎣<br />

−5 0 2 0 3 0<br />

0 −1 0 −5 0 6<br />

−1 −5 −5 2 6 3<br />

⎤<br />

⎦<br />

−20 −2 8 −10 12 12<br />

−10 −4 4 −20 6 24<br />

−1 −5 −5 2 6 3<br />

− − − − − −<br />

− − − − −<br />

− − − −<br />

− − −<br />

72 54<br />

153<br />

⎤<br />

⎥<br />

⎦<br />

⎤<br />

⎦<br />

Lös följande system<br />

[<br />

Et 72 54<br />

12A α 54 153<br />

{<br />

u3<br />

v 3<br />

}<br />

] { } {<br />

u3 P<br />

=<br />

v 3 0<br />

= 12P A [<br />

α 153 −54<br />

Et · 8100 −54 72<br />

}<br />

] { 1<br />

0<br />

}<br />

SVAR:<br />

{ }<br />

u3<br />

= P { 153<br />

v 3 50Et −54<br />

}

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