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3320d<br />
Likf ger<br />
10 − x 9<br />
= ( kors mult)<br />
9 10<br />
10(10 − x)<br />
= 9⋅9 10(10 −x) −9⋅ 9 = 0<br />
100 −10x − 81 = 0<br />
− 10x + 19 = 0<br />
x − 1, 9 = 0 ( flytta om)<br />
x = 1, 9<br />
3323b<br />
Likf ger<br />
+ 6,2<br />
4,1<br />
( flytta)<br />
( div − 10)<br />
z + 5,3 10,3<br />
= ( kors mult )<br />
5,3 4,1<br />
4,1( z + 5,3) = 5,3 ⋅10,3<br />
4,1( z + 5,3) = 5,3 ⋅10,3<br />
4,1z + 21,73 −54,59<br />
= 0<br />
4,1z − 32,86 = 0 ( div 4,1)<br />
z − 8,0 = 0 ( flytta om)<br />
z = 8, 0 cm<br />
LÖSNINGAR DEL B<br />
3322a<br />
Likf ger<br />
3+ 6<br />
x 9<br />
=<br />
8 6<br />
9<br />
x = 8⋅ = 12 cm<br />
6<br />
3324a<br />
Likf ger<br />
9− x 7,5<br />
= ( kors mult )<br />
9 12<br />
12(9 − x)<br />
= 7,5 ⋅9<br />
12(9 −x) −7,5 ⋅ 9 = 0<br />
108 −12x − 67,5 = 0<br />
− 12x + 40,5 = 0 ( div)<br />
x − 3, 4 = 0 ( flytta om)<br />
x = 3, 4 cm<br />
3325<br />
Antag att CE är x cm, då blir AE 12 – x cm.<br />
Se figur.<br />
12-x<br />
12<br />
E<br />
x<br />
A 6 D<br />
B<br />
15<br />
C<br />
(cm)<br />
( flytta)<br />
3322b<br />
Likf ger<br />
z 8<br />
=<br />
4 5<br />
8<br />
z = 4⋅ = 6,4 cm<br />
5<br />
3324b<br />
Likf ger<br />
5−2 y 3<br />
= ( kors mult )<br />
6 5<br />
5y= 3⋅6 5y= 18<br />
18<br />
y = = 3, 6 cm<br />
5<br />
Likf ger<br />
12 − x 6<br />
= ( kors mult )<br />
12 15<br />
15(12 − x)<br />
= 6⋅12 15(12 −x) −6⋅ 12 = 0<br />
180 −15x − 72 = 0<br />
− 15x + 108 = 0<br />
x − 7,2 = 0 ( flytta om)<br />
x = 7,2<br />
CE =<br />
7,2 cm<br />
( flytta)<br />
( div − 15)<br />
3323a<br />
Likf ger<br />
x 5<br />
=<br />
x + 7 11 <br />
5+ 6<br />
58<br />
( kors mult)<br />
5( x+ 7) = 11x<br />
5( x+ 7) − 11x= 0<br />
5x+ 35− 11x= 0<br />
− 6x+ 35= 0<br />
x − 5,8 = 0<br />
x = 5,8 cm<br />
( flytta om)<br />
( div − 6)<br />
( flytta om)
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