NÅGRA KOMMENTARARER TILL LÖSNINGARNA

2702a
2,5 ⋅1,5
2,5
⋅ 2,0 + = 6,9 cm
2
rektangel
triangel
2702c
2,0(2,0 + 3,5)
2⋅ = 11 cm
2
arean av 1 parallelltrapets
2703a
A = 2,6
⋅ 3,6 +
π ⋅ 1,3 = 15 cm
rektangel area cirkel area
O =
π ⋅ 2,6 + 2
⋅ 3,6 = 15 cm
cirkelns omkretsw
sidorna
2
2
2 2
2704a
A =
π ⋅2,7 /2−5,4
⋅ 2,7/2= 4,2 cm
2 2
halvcirkel triangel
2704c
A = 14 ⋅14 − π ⋅ 7 = 42 cm
2705a
a⋅ a= a
2
hela
vita
kvadrat cirkel
a ⋅ a = a
2
/2 /2
2 2 2
a − a /2 = a /2
skuggat
2
a
2 2
a /2 2 a 1
= = ⋅
2 2
a a
2 2 a
1
0,5 = 50%
2 2
=
LÖSNINGAR DEL B
2702b
3,01,5
⋅ + 1,01,0
⋅ + 3,01,5
⋅ = 10 cm
rektangel kvadrat rektangel
2702d
3,0 ⋅ 4,0
2
arean av romben
= 6,0 cm
2703b
A = 2,5
⋅4,4−
π ⋅ 1,25 / 2 = 8,5 cm
rektangel area halvcirkel area
2
2
2 2
O = 2,5
+ 4,4 + 4,4 +
π ⋅ 2,5/ 2 = 15 cm
sidorna halvcirkel omkrets
2704b
A = 2,8
⋅1,4−
π ⋅ 1,4 / 2 = 0,84 cm
rektangel halvcirkel
kvadrat kvarts cirkel
2 2
2704d
A = 4,8
⋅4,8 −
π ⋅ 4,8 / 4 = 4,9 cm
2705b
2 2
π ⋅ r /2 = πr
/2
hela
2 2
( r/2) r /4
π ⋅ = π
vita
2 2 2
πr /2 − πr /4 = πr
/4
skuggat
2
π r
2 2
πr /4 4 πr
2
= = ⋅
2
2
π r /2 π r 4 π r
2
0,5 =
50%
2 2
2
=
49