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2523<br />
s= v⋅t s<br />
t =<br />
v<br />
16<br />
4,1⋅10 t = = 8<br />
310 ⋅<br />
8<br />
1,37 ⋅10<br />
s<br />
2525a<br />
192<br />
6,02⋅10 23<br />
=<br />
−22<br />
3,2 ⋅10<br />
g<br />
192/ 6.02E23 2527a<br />
6<br />
50⋅10 ⋅ 100 =<br />
9<br />
610 ⋅<br />
0,8%<br />
2528<br />
s= v⋅t s<br />
t =<br />
v<br />
4<br />
1,05⋅10 ⋅ ⋅ =<br />
860 <br />
<br />
tiden<br />
26<br />
3,784 10 m<br />
LÖSNINGAR DEL B<br />
⋅ =<br />
1,37 ⋅10<br />
=<br />
60⋅60⋅24⋅365 4,3 år<br />
8<br />
1,37 10 s<br />
8<br />
2525b<br />
1000<br />
3, 2 ⋅10<br />
− 22<br />
=<br />
24<br />
3,1⋅10 atomer<br />
1000/3.2E-22 2527b<br />
9<br />
610 ⋅ =<br />
9<br />
610 ⋅<br />
=<br />
60⋅60⋅24⋅365 190 år<br />
3<br />
6,5 10 79360 liter<br />
förbrukningen<br />
2531<br />
9<br />
40⋅ 10 ljusår =<br />
9 8<br />
40⋅10 ⋅3⋅10 ⋅60 ⋅60⋅24⋅ 365 =<br />
⋅<br />
(3,784⋅10 )<br />
0,0004<br />
<br />
sidan i meter<br />
26 3<br />
3<br />
89<br />
8,5 10 sandkorn<br />
= ⋅<br />
år<br />
2524<br />
9<br />
1, 4 ⋅10 ⋅0,5⋅ 0,15 =<br />
8<br />
1,05⋅10 Burkar<br />
1.05E8∗0.5⋅0.15 2526<br />
Antag att det tar x dagar innan skivan är full<br />
8<br />
5000⋅50⋅ x = 6,6 ⋅10<br />
8<br />
250000x = 6,6 ⋅10<br />
8<br />
6,6 ⋅10<br />
x = = 2640 dagar<br />
250000<br />
Svar Det tar 2640 dagar innan skiva är full<br />
2527c<br />
15 år = 15⋅365⋅24⋅60⋅60 s<br />
9<br />
610 ⋅<br />
=<br />
15⋅365⋅24⋅60⋅60 13 Baspar per sekund<br />
2530a−b<br />
√ (1/ 5.92 + 1/9.85)<br />
0,520<br />
2530c−d<br />
√ + √<br />
1/ (2.32E-12) 1/ (1.27E-11) 9,37 ⋅10<br />
5<br />
41
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