NÅGRA KOMMENTARARER TILL LÖSNINGARNA

NÅGRA KOMMENTARARER TILL LÖSNINGARNA NÅGRA KOMMENTARARER TILL LÖSNINGARNA

22.09.2013 Views

2427a 20 − 15 20 + ( −15) 10 ⋅ 10 = 10 = 20−15 5 10 = 10 2427d −3 10 = 10 − 7 10 = 10 = 10 2428a −− =−− = −−− 3 ( 7) −+ 3 7 4 3 ( 2) ( 8) 8 2428d − 1 = ( −10) 1 = = 1 −10 ( 1) 1 10 2429c 1 −1 −1 ⎛2⎞ 1 (0,4) = 1 ⎜ ⎟ = = = 1 ⎝5⎠ ⎛2⎞ 2 ⎜ ⎟ ⎝5⎠ 5 1 5 5 ⋅ = = 52 1 2 2 2430a 9= 3⋅ 3= 3 2 2431a −3 2 −1 4 ⋅4 ⋅ 4 = −+− 3 2 1 −2 4 = 4 2432a 3 (0,1) = 0,001 0.1^ 3 LÖSNINGAR DEL B 2427b 10 10 10 = 10 20 20 −− ( 15) = 10 = −15 20+ 15 35 2427e 13 14 1 13 14 10⋅10 ⋅10 10 ⋅10 ⋅10 = 34 −734−7 10 ⋅10 10 ⋅10 11314 + + 28 10 10 = = 10 = 10 34 +− ( 7) 27 10 10 2428b 28−27 1 1 1 1 ( −2) −8 8 −3 −( − 2) =− =− = 3 2429a 1 −1 −1 ⎛4⎞ 4 1 4 1 3 3 ⎜ ⎟ = = = ⋅ = −1 ⎝3⎠ 3 1 4 1 4 1 3 2429d 1 −2 −2 ⎛4⎞ 1 (0,8) = 1 ⎜ ⎟ = = = 2 2 ⎝5⎠ ⎛4⎞ 4 ⎜ ⎟ 2 ⎝5⎠ 5 1 25 25 ⋅ = = 25 16 1 16 16 2430b 1 1 1 = = = 3 3 27 3⋅3⋅3 3 2431b 6 6 6 = 6 −8 −−− 8 ( 14) = 6 = −14 −+ 814 6 2432b − 3 (0,2) = 125 0.2 ^ -3 −3 2427c (10 ) = 10 = 10 −1 −2 ( −1)( ⋅ −2) 2 2427 f 0 −8 16 10 ⋅10⋅10 ⋅ 10 = 10 = 10 = 10 0++− 1 ( 8) + 16 0+−+ 1 8 16 9 2428c 2430c 813 ⋅ = 33333 ⋅ ⋅ ⋅ ⋅ 4 −6 −2 = 3 ⋅ 3 = 3 −6 −6 2431c −2 5 3 3 ⋅3 3 = = 3 −3 −3 3 3 2432c − 2 (0,5) = 4 0.5 ^ -2 10 ( 1) 1 − − =− 37 2429b 1 −2 −2 ⎛2⎞ 2 2 2 1 9 9 ⎜ ⎟ = = = ⋅ = −2 ⎝3⎠ 3 1 4 1 4 2 3 6 2430d 27 333 ⋅ ⋅ 3 = = 3 3 3 3 −− ( 4) 7 = 3 = 3 −4 −4 −4 2431d 0 10 10 5 ⋅5 5 = = 5 −2 −2 5 5 2432d − 3 (0,4) = 15,625 0.4 ^ -3 3 12

2433a 1 1 0,01 = = = 100 10⋅10 1 −2 = 10 2 10 2434a 3 −1 1 1 2 − 2 = 8− = 7 2 2 2435a 5 52 ⋅ + 3 1 5⋅ + 1 2 2 5 + 1 4 1 2 4 −2 n a + b −2 0 2436a −4 15 5x ⋅ 2x = 52 10x −4 15 ⋅ ⋅x ⋅ x = 11 2437a 4 −3 1 a ⋅ a = a = 4 a= x LÖSNINGAR DEL B 2433b 1 1 0,008 = = = 125 5⋅ 5⋅ 5 1 −3 = 5 3 5 2434b − = 1 − = 2 −2 3 3 9 2 3 1 8 9− = 8 9 9 2435b 5 + −2 a n b −2 −1 ⎛1⎞ ⎛5⎞ 5⋅ ⎜ ⎟ + ⎜ ⎟ ⎝2⎠ ⎝4⎠ 1 1 5⋅ 1 + 1 ⎛1⎞ ⎛5⎞ ⎜ ⎟ ⎜ ⎟ ⎝2⎠ ⎝4⎠ 4 4 5⋅ + 1 5 4 20 5 2436b 2 1 −8 16y 16 −8 −( −3) = y = −3 4y4 4y = 4y ( ) −+ 8 3 −5 2437b a a x = x 4 7 = a = − 3 4 7 28 2433c 1 1 1 = = = 7 2 49 7⋅ 7 7 −2 2434c 0 −1 1 5 6 + 6 = 1+ = 1 6 6 2436c t = = 3t3 4+ 6 10 4t = 4t 4 12 12 4 −− ( 6) t −6 2437c ( ) 3 5 35 ⋅ a = a = ( ) 15 4 15 60 a = x = x 38 2433d 1 1 1 = = = 5 3 125555 ⋅ ⋅ 5 2434d −2 −3 1 1 3 + 2 = + = 2 3 3 2 1 1 17 + = 9 8 72 2436d x −6x−6 −5 −3x 5 18 18 5−10 = x = 10 2437d 2 −2 6 ( a ⋅ x ) = 2 −2 ( a ) ( x ) ( ) 6 6 ⋅ = 12 −12 a ⋅ x = 4 12 −12 x ⋅ x = x ⋅ x = x 48 −12 36 −3

2433a<br />

1 1<br />

0,01 = = =<br />

100 10⋅10 1 −2<br />

= 10 2<br />

10<br />

2434a<br />

3 −1<br />

1 1<br />

2 − 2 = 8− = 7<br />

2 2<br />

2435a<br />

5<br />

52 ⋅ + 3<br />

1<br />

5⋅ + 1 2<br />

2<br />

5<br />

+ 1<br />

4<br />

1<br />

2<br />

4<br />

−2<br />

n<br />

a + b<br />

−2<br />

0<br />

2436a<br />

−4<br />

15<br />

5x ⋅ 2x<br />

=<br />

52<br />

10x<br />

−4<br />

15<br />

⋅ ⋅x ⋅ x =<br />

11<br />

2437a<br />

4 −3<br />

1<br />

a ⋅ a = a =<br />

4<br />

a= x<br />

LÖSNINGAR DEL B<br />

2433b<br />

1 1<br />

0,008 = = =<br />

125 5⋅ 5⋅ 5<br />

1 −3<br />

= 5 3<br />

5<br />

2434b<br />

− =<br />

1<br />

− =<br />

2 −2<br />

3 3 9 2<br />

3<br />

1 8<br />

9− = 8<br />

9 9<br />

2435b<br />

5 +<br />

−2<br />

a<br />

n<br />

b<br />

−2 −1<br />

⎛1⎞ ⎛5⎞ 5⋅<br />

⎜ ⎟ + ⎜ ⎟<br />

⎝2⎠ ⎝4⎠ 1 1<br />

5⋅<br />

1 + 1<br />

⎛1⎞ ⎛5⎞ ⎜ ⎟ ⎜ ⎟<br />

⎝2⎠ ⎝4⎠ 4 4<br />

5⋅ +<br />

1 5<br />

4<br />

20 5<br />

2436b<br />

2 1<br />

−8<br />

16y 16 −8 −( −3)<br />

= y =<br />

−3<br />

4y4 4y = 4y<br />

( )<br />

−+ 8 3 −5<br />

2437b<br />

a<br />

a<br />

x = x<br />

4<br />

7<br />

= a =<br />

− 3<br />

4<br />

7<br />

28<br />

2433c<br />

1 1 1<br />

= = = 7 2<br />

49 7⋅ 7 7<br />

−2<br />

2434c<br />

0 −1<br />

1 5<br />

6 + 6 = 1+ = 1<br />

6 6<br />

2436c<br />

t<br />

= =<br />

3t3 4+ 6 10<br />

4t = 4t<br />

4<br />

12 12 4 −− ( 6)<br />

t<br />

−6<br />

2437c<br />

( )<br />

3<br />

5<br />

35 ⋅<br />

a = a =<br />

( )<br />

15 4<br />

15<br />

60<br />

a = x = x<br />

38<br />

2433d<br />

1 1 1<br />

= = = 5 3<br />

125555 ⋅ ⋅ 5<br />

2434d<br />

−2 −3<br />

1 1<br />

3 + 2 = + =<br />

2 3<br />

3 2<br />

1 1 17<br />

+ =<br />

9 8 72<br />

2436d<br />

x<br />

−6x−6 −5<br />

−3x<br />

5<br />

18 18 5−10 = x =<br />

10<br />

2437d<br />

2 −2<br />

6<br />

( a ⋅ x ) =<br />

2 −2<br />

( a ) ( x )<br />

( )<br />

6 6<br />

⋅ =<br />

12 −12<br />

a ⋅ x =<br />

4<br />

12<br />

−12<br />

x ⋅ x =<br />

x ⋅ x =<br />

x<br />

48 −12<br />

36<br />

−3

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