NÅGRA KOMMENTARARER TILL LÖSNINGARNA

5344e
k =− 1 m=
3
y=− x+
3
5345
(7, 4) (2, −
6)
x1 y2 x2
y2
−6−4 k =
2−7 k = 2
(1, − 3)
k = 2
x1 y2
( 3) 2( 1)
y− − = x−
y= 2x−5 5348
(50, 4) (130,8)
q1 T2
q2 T2
8−4 k =
130 − 50
k = 0,05
T − 4= 0,05 q−50
T = 0,05q+ 1,5
5350a
( )
LÖSNINGAR DEL B
5344 f
k =− 1 m=−4
y =−x−4 5346
(2,28) (5,40)
x1 y1 x2 y2
40 − 28
k =
5−2 k = 4
y− 28 = 4 x−2
y = 4x+ 20
( )
5349
(500,15) (10000, −
80)
x1 y2 x2 y2
−80 −15
k =
10000 − 500
k =−0,01
y− 15 =−0,01 x−500
y=− 0,01x+ 20
5350b
( )
5347
(15,76.45) (100,76.56)
t1 L1 t2 L2
76,56 − 76,45
k =
100 −15
k
= 0,0013
Avrundat
( )
L− 76,45 = 0,0013 t−15
L= 0,0013t+ 76,43
5350c
5350d
y = 0x+ 3 m
y= 0,5x+ 2 m
y = − x+
1 m
y = 2x+ 0 m
linje S
linje R
linje P
linje Q
5350e
( )
y = 0x+ − 5
linje T
m
5354a
7x+ y+
4= 0
y=−7x−4 k =− 7 m=−4
5354b
2x+ y−
9= 0
y =− 2x+ 9
k =− 2 m=
9
5354c
15x+ 5y+ 10 = 0
5y=−15x−10 y=−3x−2 k = − 3 m=−2
5354d
4x+ 4y− 12= 0
4y =− 4x+ 12
y =− x+
3
k =− 1 m=
3
101