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472 P a r t V I : A n t e n n a s f o r O t h e r F r e q u e n c i e s<br />

Solution<br />

P<br />

P<br />

=<br />

4πr<br />

d 2<br />

= (1000W)<br />

4π (1000m)<br />

= 7.95×<br />

10 W / m<br />

2<br />

–5 2<br />

<br />

The rest of this chapter expresses antenna gains and directivities relative to isotropic<br />

radiators.<br />

Near Field and Far Field<br />

<strong>Antenna</strong>s are defined in terms of gain and directivity, both of which are measured by<br />

examining the radiated field of the antenna. Published antenna patterns usually report<br />

only far-field performance. In free space, the far field for most antennas falls off according<br />

to the inverse square law. That is, the intensity falls off according to the square of the<br />

distance (1/r 2 ), as in Eq. (20.19).<br />

The near field of the antenna contains more energy than the far field because of its<br />

proximity to the antenna radiator element, but it diminishes very rapidly with increasing<br />

distance according to a 1/r 4 function. The minimum distance to the edge of the near field<br />

is a function of both the wavelength of the radiated signals and the antenna dimensions:<br />

r<br />

min<br />

= 2d<br />

l<br />

where r min = near-field distance<br />

d = largest antenna dimension<br />

l = wavelength of radiated signal (all factors in same units)<br />

2<br />

(20.20)<br />

Example 20.6 An antenna with a length of 6 cm radiates a 12-cm wavelength signal.<br />

Calculate the near-field distance.<br />

Solution<br />

r<br />

min<br />

= 2d<br />

l<br />

=<br />

2<br />

= 72<br />

12<br />

= 6 cm<br />

(2) (6 cm)<br />

12 cm<br />

2

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