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C h a p t e r 2 0 : M i c r o w a v e W a v e g u i d e s a n d A n t e n n a s 459<br />

We can define a general mode equation based on our system of notation:<br />

1<br />

( )<br />

λ C<br />

2<br />

2 2<br />

⎛ m ⎞ ⎛ n ⎞<br />

= ⎜ ⎟ + ⎜ ⎟<br />

⎝ 2 a ⎠ ⎝ 2 b⎠<br />

(20.7)<br />

where l c = longest wavelength that will propagate<br />

a, b = waveguide dimensions (see Fig. 20.2)<br />

m, n = integers defining number of half-wavelengths that will fit in a and b<br />

dimensions, respectively<br />

Evaluating Eq. (20.7) reveals that the longest TE-mode signal that will propagate in<br />

the dominant mode (TE 10 ) is given by<br />

from which we can write an expression for the cutoff frequency:<br />

lc = 2a<br />

(20.8)<br />

f<br />

c<br />

c<br />

=<br />

2a<br />

(20.9)<br />

where f c = lowest frequency that will propagate, in hertz<br />

c = speed of light (3 ×10 8 m/s)<br />

a = wider of the two waveguide dimensions<br />

Example 20.3 A rectangular waveguide has dimensions of 3 × 5 cm. Calculate the TE 10<br />

mode cutoff frequency.<br />

Solution<br />

f<br />

c<br />

c<br />

=<br />

2a<br />

=<br />

(3×<br />

108 m / s<br />

⎛ 1 m ⎞<br />

(2) ⎜5 cm × ⎟<br />

⎝ 100 cm ⎠<br />

×<br />

= 3 10 8<br />

m / s<br />

(2) (0.05 m)<br />

= 3 GHz

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