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448 P a r t V I : A n t e n n a s f o r O t h e r F r e q u e n c i e s<br />

resistance with increasing frequency. Dielectric losses are caused by the electric field<br />

acting on the molecules of the insulator, thereby causing heating through molecular<br />

agitation, and tend to be largest when the wavelength is comparable to the interatomic<br />

resonances of the dielectric. Radiation losses result from incomplete shielding (in a coaxial<br />

line) or from imbalance and incomplete cancellation of RF in the two sides of the<br />

line—usually because at some frequency the spacing between the wires becomes too<br />

large a percentage of the RF signal wavelength. All these losses are proportional to both<br />

frequency and transmission line length and serve to limit both the maximum power<br />

that can be applied at the transmitter end of the line and the maximum frequency for a<br />

given line length.<br />

To circumvent these problems, waveguides are used. What is a waveguide? Probably<br />

the simplest response is to say that a waveguide is to radio waves what an optical fiber<br />

is to light waves. Each is a hollow tube or tunnel through which an electromagnetic<br />

wave is “encouraged” by the tube’s characteristics to pass. Consider the light pipe analogy<br />

depicted in Fig. 20.1. A flashlight serves as our RF source, which (given that light is<br />

also an electromagnetic wave) is not altogether unreasonable. In Fig. 20.1A the source<br />

radiates into free space and spreads out as a function of distance. The intensity per unit<br />

area falls off as a function of distance (D) according to the inverse square law (1/D 2 ).<br />

But now consider the transmission scheme in Fig. 20.1B. The light wave still propagates<br />

over distance D but is now confined to the interior of a mirrored pipe. Almost all<br />

of the energy coupled to the input end is delivered to the output end, where the intensity<br />

is practically undiminished. Although not perfect, the light pipe analogy illuminates<br />

(pardon the pun . . . again) the value of microwave waveguides. Similarly,<br />

fiber-optic technology is waveguide-like at optical (IR and visible) wavelengths. In fact,<br />

the analogy between fiber optics and waveguide is a more rigorous comparison than<br />

the simplistic light pipe analogy.<br />

D<br />

A<br />

Large diffused beam<br />

"Light pipe"<br />

B<br />

Small intense beam<br />

Figure 20.1 Waveguide analogy to light pipe.

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