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C h a p t e r 6 : D i p o l e s a n d D o u b l e t s 195<br />

L<br />

300-<br />

parallel<br />

line or<br />

twin lead<br />

To<br />

XMTR<br />

Figure 6.11A Folded dipole fed with 300-Ω line.<br />

Assuming we can match the 300-Ω line to the transmitter, we have the same power<br />

going into the folded dipole as we did into the single-wire dipole. For equal power, if<br />

one feedpoint current is half the other, its corresponding feedpoint voltage must be<br />

twice the other (because P = VI = constant). Thus, in free space the transmission line<br />

“sees” a feedpoint impedance of<br />

Z<br />

FOLDED<br />

2V<br />

=<br />

I<br />

2<br />

V<br />

= 4<br />

I<br />

= 4Z<br />

DIPOLE<br />

DIPOLE<br />

DIPOLE<br />

DIPOLE<br />

DIPOLE<br />

≈ 290 Ω<br />

(6.9)<br />

The impedance step-up ratio for a two-wire folded dipole is 4:1 if the two conductors<br />

are of equal diameter. When they’re not, the relationship is more complicated but the<br />

impedance step-up is generally proportional to the ratio of the unfed wire diameter to<br />

the fed wire diameter. Thus, a folded dipole can be designed to provide a specific feedpoint<br />

impedance to the transmitter and transmission line, within limits, by making one<br />

of the two wires larger than the other.<br />

In many installations, the best feedline for the folded dipole will be 300-Ω twin-lead<br />

or, better yet, open-wire line connected to a balanced wire ATU at the transmitter end.

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