Practical_Antenna_Handbook_0071639586
C h a p t e r 6 : D i p o l e s a n d D o u b l e t s 179 Z 2500 (end) Figure 6.2 Graph of current, voltage, and impedance along half-wavelength dipole. E I 73 (center) /2 120 100 90 Radiation resistance R r 80 72 70 60 50 Free space R r Height above ground (wavelengths) 40 30 20 10 0 0 /4 /2 3/4 5/4 3/2 7/4 2 9/4 5/2 Figure 6.3 Radiation resistance versus height above ground.
180 p a r t I I I : h i g h - F r e q u e n c y B u i l d i n g - B l o c k A n t e n n a s is because some of the signal radiated by the dipole strikes the ground directly beneath the antenna and is reflected straight up, where it induces a second field within the dipole. Because of the time it takes the radiated field to reach the ground and return, the induced field is shifted in phase with respect to the original signal in the dipole. This causes the ratio of voltage to current at the feedpoint to vary with the height of the antenna, which is simply saying the feedpoint impedance varies with height. At heights of many wavelengths, this oscillation of the curve settles down to the free-space impedance (73 Ω) as the effect of the earth becomes negligible. At the higher frequencies (VHF and above), it becomes practical to install a dipole at a height of many wavelengths. In the 2-m amateur radio band (144 to 148 MHz), λ ≈ 6.5 ft (i.e., 2 m × 3.28 ft/m), so a height of “many wavelengths” is relatively easy to achieve. In the 80-m band (3.5 to 4.0 MHz), however, λ ≈ 262 ft, so “many wavelengths” is a virtual impossibility for most. Any of a number of alternative responses can be chosen: • Ignore the problem altogether. In many installations, the height above ground will be such that the radiation resistance will be close enough to represent only a slight impedance mismatch to a standard coaxial cable. For Z 0 > R RAD , the voltage standing wave ratio (VSWR) is calculated (among other ways) as the ratio For Z 0 < R RAD , it is the ratio Z0 VSWR = (6.5) R RAD where Z 0 = coaxial cable characteristic impedance R RAD = radiation resistance of antenna RRAD VSWR = (6.6) Z • Consider mounting the antenna at a height somewhat below a quarterwavelength, such that the radiation resistance is around 60 Ω. What is the resulting VSWR when feeding a 60-Ω antenna with either 52- or 75-Ω standard coaxial cable? Some calculations reveal: For 75-Ω coaxial cable: Z VSWR = R 0 RAD 0 75 = 60 = 1.25 : 1
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180 p a r t I I I : h i g h - F r e q u e n c y B u i l d i n g - B l o c k A n t e n n a s<br />
is because some of the signal radiated by the dipole strikes the ground directly beneath<br />
the antenna and is reflected straight up, where it induces a second field within<br />
the dipole. Because of the time it takes the radiated field to reach the ground and return,<br />
the induced field is shifted in phase with respect to the original signal in the<br />
dipole. This causes the ratio of voltage to current at the feedpoint to vary with the<br />
height of the antenna, which is simply saying the feedpoint impedance varies with<br />
height. At heights of many wavelengths, this oscillation of the curve settles down to<br />
the free-space impedance (73 Ω) as the effect of the earth becomes negligible. At the<br />
higher frequencies (VHF and above), it becomes practical to install a dipole at a height<br />
of many wavelengths. In the 2-m amateur radio band (144 to 148 MHz), λ ≈ 6.5 ft (i.e.,<br />
2 m × 3.28 ft/m), so a height of “many wavelengths” is relatively easy to achieve. In<br />
the 80-m band (3.5 to 4.0 MHz), however, λ ≈ 262 ft, so “many wavelengths” is a virtual<br />
impossibility for most.<br />
Any of a number of alternative responses can be chosen:<br />
• Ignore the problem altogether. In many installations, the height above ground<br />
will be such that the radiation resistance will be close enough to represent only<br />
a slight impedance mismatch to a standard coaxial cable. For Z 0 > R RAD , the<br />
voltage standing wave ratio (VSWR) is calculated (among other ways) as the<br />
ratio<br />
For Z 0 < R RAD , it is the ratio<br />
Z0<br />
VSWR = (6.5)<br />
R<br />
RAD<br />
where Z 0 = coaxial cable characteristic impedance<br />
R RAD = radiation resistance of antenna<br />
RRAD<br />
VSWR = (6.6)<br />
Z<br />
• Consider mounting the antenna at a height somewhat below a quarterwavelength,<br />
such that the radiation resistance is around 60 Ω. What is the<br />
resulting VSWR when feeding a 60-Ω antenna with either 52- or 75-Ω standard<br />
coaxial cable? Some calculations reveal:<br />
For 75-Ω coaxial cable:<br />
Z<br />
VSWR =<br />
R<br />
0<br />
RAD<br />
0<br />
75<br />
=<br />
60<br />
= 1.25 : 1