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144 P a r t I I : F u n d a m e n t a l s<br />

Z L<br />

Load<br />

impedance<br />

Example 4.9 A 50-Ω source must be matched to a load impedance<br />

of 36 Ω. Find the characteristic impedance required of a<br />

Q-section matching network.<br />

Solution<br />

Z0<br />

=<br />

Z Z<br />

S<br />

L<br />

= (50 Ω) (36 Ω)<br />

= 1800 Ω<br />

= 42 Ω<br />

2<br />

Z o<br />

Z s<br />

/4 Q section<br />

Figure 4.12 Quarter-wavelength<br />

Q section.<br />

<br />

Clearly, the key to success is to have available a piece of<br />

transmission line having the required characteristic impedance.<br />

Unfortunately, the number of different coaxial cable impedances<br />

available for the Q-section is limited, and so its<br />

utility for matching an arbitrary pair of impedances is also<br />

limited.<br />

On open-wire transmission line systems, on the other<br />

hand, it is quite easy to achieve the correct impedance for the<br />

matching section. As before, we use the preceding equation to<br />

find a value for Z 0 , and then calculate the conductor spacing<br />

and diameter needed for a short length of a custom transmission<br />

line! Armed with information about the diameter of common<br />

wire sizes, once we know the feedpoint impedance, we<br />

can use Eq. (4.55) to calculate the appropriate conductor spacing:<br />

S = d × 10<br />

( Z0<br />

/ 276)<br />

(4.55)<br />

where S = spacing between conductors of parallel line<br />

d = conductor diameter expressed in same units as S<br />

Z 0 = desired surge impedance for Q-section<br />

Assuming true open-wire line (with air dielectric) is used, the length of the<br />

quarter-wave section in feet can be calculated using the familiar 246/F, where F is in<br />

megahertz.<br />

A quarter-wavelength shorted stub is a special case of the stub concept that finds particular<br />

application in microwave circuits. Waveguides (Chap. 20) are based on the properties<br />

of the quarter-wavelength shorted stub. Figure 4.13 shows a quarter-wave stub<br />

and its current distribution. The current is maximum across the short, but wave cancellation<br />

forces it to zero at the terminals. Because Z = V/I, when I goes to zero, the impedance<br />

becomes infinite. Thus, a quarter-wavelength stub has an infinite impedance at its<br />

resonant frequency, and acts as an insulator. This concept may be hard to swallow, but<br />

the stub is a “metal insulator”.

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