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C h a p t e r 4 : T r a n s m i s s i o n L i n e s a n d I m p e d a n c e M a t c h i n g 141<br />

In general, the simplest ways to determine Z IN as a function of feedline length for a<br />

specific load are to use the graphical Smith chart techniques of Chap. 26 or one of the<br />

many online calculators available. However, when the load on a nearly lossless length<br />

of line is either a short circuit or an open circuit, the math required to find Z IN for a given<br />

length of line is quite a bit simpler and yields interesting and useful results.<br />

For a short circuit at the far end of the line, Z L = 0, and Eq. (4.42) reduces to<br />

Z<br />

IN−SHORT 0<br />

⎡0 + jZ0<br />

tan βl<br />

⎤<br />

= Z ⎢<br />

⎥ = jZ<br />

⎣ Z + j0<br />

⎦<br />

0<br />

( )<br />

0<br />

tan( βl)<br />

(4.43)<br />

Since the only term in the solution is imaginary, Z IN is purely reactive—alternating<br />

between capacitive and inductive reactance as the length of the short-circuited line is<br />

varied and tan (bl) swings negative or positive, respectively.<br />

Similarly, for an open circuit at the far end of the line, Z L = ∞, and Eq. (4.42)<br />

reduces to<br />

⎡ 1 ⎤<br />

ZIN -OPEN<br />

= Z0 ⎢ ⎥ = −jZ0<br />

cot ( β l)<br />

⎣ j tan( β l )<br />

(4.44)<br />

⎦<br />

Note: If you have a network analyzer, VNA, or antenna analyzer that provides R and X for an<br />

unknown impedance attached to its terminals, you can determine Z 0 and the velocity factor<br />

(v F ) for a mystery piece of transmission line. First obtain Z IN-OPEN and Z IN-SHORT for the line.<br />

Now multiply Eq. (4.43) by Eq. (4.44) to obtain Eq. (4.45):<br />

( Z )( Z ) = ⎡⎣ jZ tan( βl) ⎤ ⎦ ⎡⎣ −Z cot( βl)<br />

⎤ (4.45)<br />

⎦<br />

IN-SHORT IN-OPEN 0 0<br />

But tan x = 1/cot x, so Eq. (4.45) reduces to<br />

2 2 2<br />

( Z )( Z ) = − j Z = Z<br />

(4.46)<br />

IN -SHORT<br />

IN -OPEN<br />

0<br />

0<br />

In other words, we can determine the characteristic impedance of our unlabeled transmission<br />

line by taking the square root of the product of the short-circuit and open-circuit impedance<br />

measurements we made.<br />

If now we obtain the ratio of Eqs. (4.43) and (4.44), we have<br />

Z<br />

Z<br />

IN-SHORT<br />

IN -OPEN<br />

jZ0<br />

tan βl<br />

2<br />

=<br />

tan ( l)<br />

−jZ<br />

cot β l<br />

= − β (4.47)<br />

0<br />

( )<br />

( )<br />

Multiplying both sides by -1 and taking the positive square root, we obtain<br />

ZIN-SHORT<br />

tan( β l)<br />

= − (4.48)<br />

Z<br />

IN -OPEN

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