Practical_Antenna_Handbook_0071639586
C h a p t e r 4 : T r a n s m i s s i o n L i n e s a n d I m p e d a n c e M a t c h i n g 137 When both ends of the line are mismatched, a different equation is required: ML = 20 log [ 1± ( Γ 1 × Γ 2 )] (4.39) where G 1 = reflection coefficient at source end of line (VSWR 1 – 1)/(VSWR 1 + 1) G 2 = reflection coefficient at load end of line (VSWR 2 – 1)/(VSWR 2 + 1) Note that the solution to Eq. (4.39) has two values: [1 + (G 1 G 2 )] and [1 – (G 1 G 2 )]. The equations reflect the mismatch loss solution for low-loss or “lossless” transmission lines. This is a close approximation in many situations; however, even cables having minimal loss at HF exhibit substantially higher losses at microwave frequencies. Interference between forward and reflected waves produces increased current at certain antinodes—which increases ohmic losses—and increased voltage at certain antinodes—which increases dielectric losses. It is the latter that increases with frequency. Equation (4.40) relates line losses to the reflection coefficient to determine total loss on a line with a given VSWR. ⎛ 2 2 n – Γ ⎞ Loss = 10 log ⎜ ⎟ 2 ⎝ n – nΓ ⎠ (4.40) where loss = total line loss in decibels G = reflection coefficient n = quantity 10 (A/10) A = total attenuation presented by line, in decibels, when line is properly matched (Z L = Z 0 ) Example 4.8 A 50-Ω transmission line is terminated in a 30-Ω resistive impedance. The line is rated at a loss of 3 dB/100 ft at 1 GHz. Calculate (a) loss in 5 ft of line, (b) reflection coefficient, and (c) total loss in a 5-ft line mismatched per above. Solution ( a) A = 3 dB × 5 ft 100 ft = 0.15 dB Z ( b) Γ = Z L L – Z + Z 0 0 50 – 30 = 50 + 30 = 20 / 80 = 0.25 ( c) n = 10 = 10 = 10 = 1.04 ( A/10) (0.15/10) (0.015)
138 P a r t I I : F u n d a m e n t a l s ⎛ 2 2 n – Γ ⎞ Loss = 10 log ⎜ 2 ⎟ ⎝ n – nΓ ⎠ ⎡ = 10 log ⎢ ⎣ ⎡ = 10 log ⎢ ⎣ ⎛ = 10 log ⎜ ⎝ ⎛ ⎞ = 10 log ⎜ 1.019 ⎟ ⎝ 0.974 ⎠ = 10 log (1.046) = (10) (0.02) = 0.2 dB 2 2 (1.04) – (0.25) 1.04 – (1.04) (0.25) 1.082 – 0.063 1.04 – (1.04) (0.063) 1.019 1.04 – 0.066 ⎞ ⎟ ⎠ 2 ⎤ ⎥ ⎦ ⎤ ⎥ ⎦ Compare the matched line loss (A = 0.15 dB) with the total loss (Loss = 0.2 dB), which includes mismatch loss and line loss. The difference (i.e., Loss – A) is only 0.05 dB. If the VSWR or the total line length were considerably larger, however, the loss would rise. Impedance Matching in Antenna Systems Although antennas are reciprocal devices, a receiving antenna can do an excellent job even in the absence of perfect matches between the antenna and the feedline or between the feedline and the receiver. This is especially true in the MF and lower HF regions, where reception is almost always limited by atmospheric noise. In contrast, proper matching of the transmitter to the feedline and the feedline to the antenna is essential for maximizing our radiated signal. That is because maximum power transfer between a source and a load always occurs when the system impedances are matched. Of course, the trivial situation is when all three sections of our system—transmitter, feedline, and antenna—have the same impedance. The most obvious example would be an antenna (such as a half-wave dipole in free space) with a 75-Ω resistive feedpoint impedance fed from garden variety 75-Ω coaxial cable or hardline that is connected to a transmitter with a 75-Ω output impedance. However, in real life the feedpoint impedance is rarely what the books say it should be. Even our ubiquitous l/2 dipole seldom appears to be exactly 75 Ω or purely resistive to its feedline. Then there are our wire arrays, our Yagis and our loops—all with
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138 P a r t I I : F u n d a m e n t a l s<br />
⎛<br />
2 2<br />
n – Γ ⎞<br />
Loss = 10 log ⎜<br />
2<br />
⎟<br />
⎝ n – nΓ<br />
⎠<br />
⎡<br />
= 10 log ⎢<br />
⎣<br />
⎡<br />
= 10 log ⎢<br />
⎣<br />
⎛<br />
= 10 log ⎜<br />
⎝<br />
⎛ ⎞<br />
= 10 log ⎜<br />
1.019 ⎟<br />
⎝ 0.974 ⎠<br />
= 10 log (1.046)<br />
= (10) (0.02)<br />
= 0.2 dB<br />
2 2<br />
(1.04) – (0.25)<br />
1.04 – (1.04) (0.25)<br />
1.082 – 0.063<br />
1.04 – (1.04) (0.063)<br />
1.019<br />
1.04 – 0.066<br />
⎞<br />
⎟<br />
⎠<br />
2<br />
⎤<br />
⎥<br />
⎦<br />
⎤<br />
⎥<br />
⎦<br />
Compare the matched line loss (A = 0.15 dB) with the total loss (Loss = 0.2 dB),<br />
which includes mismatch loss and line loss. The difference (i.e., Loss – A) is only 0.05<br />
dB. If the VSWR or the total line length were considerably larger, however, the loss<br />
would rise.<br />
<br />
Impedance Matching in <strong>Antenna</strong> Systems<br />
Although antennas are reciprocal devices, a receiving antenna can do an excellent job<br />
even in the absence of perfect matches between the antenna and the feedline or between<br />
the feedline and the receiver. This is especially true in the MF and lower HF regions,<br />
where reception is almost always limited by atmospheric noise.<br />
In contrast, proper matching of the transmitter to the feedline and the feedline to<br />
the antenna is essential for maximizing our radiated signal. That is because maximum<br />
power transfer between a source and a load always occurs when the system impedances<br />
are matched.<br />
Of course, the trivial situation is when all three sections of our system—transmitter,<br />
feedline, and antenna—have the same impedance. The most obvious example would be<br />
an antenna (such as a half-wave dipole in free space) with a 75-Ω resistive feedpoint<br />
impedance fed from garden variety 75-Ω coaxial cable or hardline that is connected to a<br />
transmitter with a 75-Ω output impedance.<br />
However, in real life the feedpoint impedance is rarely what the books say it should<br />
be. Even our ubiquitous l/2 dipole seldom appears to be exactly 75 Ω or purely resistive<br />
to its feedline. Then there are our wire arrays, our Yagis and our loops—all with